Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:
Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.81 times.
Answer:
c
Explanation:
because you cant really see the other ones dark text wont show up on a dark background light text wont show up on a light back ground.
Answer:
Program :
number=int(input("Enter the number: "))#take the input from the user.
number1=number
count=0#take a variable for count.
while(number>0):#loop which check every number to be odd or not.
value=number%10 #it is used to take the every number from integer value.
number=int(number/10)#it is used to cut the number which is in the use.
if(value%2!=0):#It is used to check the number to be odd.
count=count+1#It is used to increase the value.
print("The number of Odd Digits in "+str(number1)+" is "+str(count))#It is used to print the count value of odd digit.
Output:
- If the user inputs is '1234567890', it will prints "5".
- If the user inputs is "8546587", it will prints "3".
Explanation:
- The above program is in python language, which takes the integer value from the user.
- Then The number will be distributed into many individual units with the help of a while loop.
- The while loop runs when the number is greater than 0.
- There is a two operation, one is used to take the number by the help of modulo operator because it gives the remainder.
- The second operation is used to divide the number to let the number 0.
Answer:
Provide requested web pages to clients; the other tasks listed there are secondary to that.
The answer should be: True
