All categories

3 years ago

7p-2=4p-4 how to solve this hdjnffkkrmfmfkfkrjfjffjfkfkmffkcockcickfifkkfkfkfkfkfkffmf

Mathematics

2 answers:

Andrew [12]3 years ago

8 0

Answer: -2/3

Step-by-step explanation:

7p-2 = 4p -4

solution,

or, 7p-2=4p-4

or, 7p-4p=-4+2

or, 3p= -2

or, p=-2/3

therefore, p=-2/3#

lapo4ka [179]3 years ago

6 0

Answer:

7p-2 = 4p-4

7p-4p = 2-4

3p = -2

p = -2/3

Hope this helps!

You might be interested in

6x - 3y = -6<br> y = 2x + 2

Verizon [17]

Answer:

y=0, x=1

Step-by-step explanation:

6x-3y= -6 ...... equation 1

y =2x+2 ..... equation 2

subtract 2x from both sides

y-2x=2x-2x+2

y-2x=2

6x-3y= -6

y-2x=2

Rearrange

6x-3y= -6 ........x1

-2x +y=2............x3

6x-3y= -6

-6x +3y=2

0y=0

y=0

substitute y=0 in equation 1

6x-3xo= -6

6x= -6

x-6/6

x = -1

4 0

3 years ago

Find the midpoint of the segment with the given endpoints.<br> (7,10) and (-1,-8)

lara31 [8.8K]

Answer:

Step-by-step explanation:

Hi guy I just wanted to say have a very good day and I hope you are alright today and I hope this helped out your day alright peace out

7 0

3 years ago

What is the answer to (z+1)(z+2)

stich3 [128]

Answer:

z^1+3z+2

Step-by-step explanation:

(z+1)(z+1)

Multiply each term in the first parenthesis by each term in the second parenthesis

Z x z+2z+z+2

Calculate the product

<u>z</u>^2 +2z+z+2

collect like terms

z^2+3z+2

2z+z

If a term doesnt have a coefficient it is considered that the coefficient is 1

2z+1z

(2+1)z

z^2+3z+2

4 0

3 years ago

Read 2 more answers

Which is true regarding the graphed function f(x)?

Sladkaya [172]

<h2>Explanation:</h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here I'll assume the graphed function comes from:

$f(x)=\left(x-4\right)^{2}+5$

So this is the equation of a parabola that opens upward and whose vertex lies on the point:

$V(4,5)$

The graph of this function is shown below. Which is true regarding the graphed function f(x)?

It is true that the domain is the set of all real numbers because this is a polynomial function.

It is true that the range is the set of all real numbers such that y ≥ 5

It is true that this parabola opens upward

It is true that it doesn't cut the x-axis

6 0

3 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0

3 years ago