<span>A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (left figure). The perpendicular bisector
of a line segment can be constructed using a compass by drawing circles
centered at and with radius and connecting their two intersections.
Hope i helped
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Answer:
b
Step-by-step explanation:
First of all, you have to calculate slope of that,
m = (y2-y1)/(x2-x1) = (1-0)/(0+2) = 1/2
now, equation would be y-y1 = m(x-x1)
y-1 = 1/2(x-0)
y-1 = x/2
y = x/2+ 1
Answer:

Step-by-step explanation:
we know that
The given equation y=5 is a horizontal line (is parallel to the x-axis)
The slope of the given line is equal to zero
A perpendicular line to the given line is a vertical line (parallel to the y-axis)
so
The equation of a vertical line is equal to the x-coordinate of the point that passes through it
The point that passes through it is (-4,-6)
therefore
The equation of the perpendicular line is
