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xxTIMURxx [149]
4 years ago
8

Mr.Romero's class solves 23word problems every day monday through friday for three how many total math problems did Mr.Romero's

class solve in those three weeks
Mathematics
1 answer:
Fiesta28 [93]4 years ago
8 0

Answer:

Step-by-step explanation:

So, it might be... 23×7=161. Hope it helps!

Idk if I'm wrong tho

You might be interested in
Question 4
laiz [17]

Answer:

I just solved a question similar to this

Let's understand it

It's saying she got 660 or it is that her weekly pay is 660

So now let weekly pay which is P be 660

Hence the formulae is given

It's 480 + 18 (h – 30) = 660

Now its just boring calculation

If you mark it brainleist I will do the calculation for you wink wink

Never mind

480 + 18 (h – 30) = 660

18 (h – 30) = 660-480

18 (h – 30) = 120

(h – 30) = 120/18

(h – 30) = 6.6

h = 6.6+30

h= 36.6

So dam the Judy lady worked for 36.6 hours

5 0
3 years ago
PLEASE SOMEONE HELP!!!!!!!!!!!!!!
dezoksy [38]
<1 and <2 are supplementary angles. They add up to 180 degrees.

92 and <2 are corresponding angles, they have the same measure.

So,<2 = 92 degrees

180-92= 88 degrees

<1= 88 degrees

I hope this helps!
~kaikers
7 0
4 years ago
Please help, will give brainlist
Marrrta [24]

Answer:

8

Step-by-step explanation:

compare the divisor x+1 with x-a which will be -1 then use remainder theorem to get your answer

5 0
3 years ago
How is 4/50 written as a percent
Leona [35]
8% 
4 ÷ 50 is 0.08 x 100 is 8%
8 0
3 years ago
Read 2 more answers
Please view the picture for the problem.
Tema [17]
Notice that we have common denominator 2, so we can split the denominator to express the function in the form f(x)=mx+b
where 
m is the slope 
b is the y-intercept 

f(x)= \frac{3x-1}{2}
f(x)= \frac{3}{2} x- \frac{1}{2}
Look what we have here, a linear function! We know that the domain and range of linear functions is the real numbers.
We can conclude that:
the domain of the function is all the real numbers
the range of the function is all the real numbers

Now, to find the inverse of our function, we are going to replace f(x) with y; then, we are going to interchange x and y and solve for y:
f(x)= \frac{3}{2} x- \frac{1}{2}
y= \frac{3}{2} x- \frac{1}{2}
x=\frac{3}{2} y- \frac{1}{2}
\frac{3}{2} y=x+ \frac{1}{2}
3y=2x+1
y= \frac{2}{3} x+ \frac{1}{3}
f^{-1}(x)=\frac{2}{3} x+ \frac{1}{3}
The inverse of our linear function, is another linear function, so we can conclude that:
the domain of the inverse function is all the real numbers
the range of the inverse function is all the real numbers
4 0
4 years ago
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