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marin [14]
3 years ago
7

H(a)=2a+4 g(a)-2a^2+2 find (h+g)(a+3)

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

hello :  

(g/f)(3) = g(3)/f(3)

but : g(3) =3(3)+2 = 11

f(3) 2(3)-4 = 2

g/f)(3) = 11/2

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A certain television is advertised as a 21-inch TV (the diagonal length). If the height of the TV is 13 inches, how wide is the
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1 Point
I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

7 0
3 years ago
Please help me with this thank you !!
andreev551 [17]
I think the answer is b i've never learned this sorry :(
4 0
3 years ago
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timofeeve [1]

Answer:

The answer is 2/5 or 5.25

Step-by-step explanation:

5 sections so out of 5 and it said A or B so it is 2/5

5 0
2 years ago
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