The mathematical expression that is equivalent to negative two raised to the fourth power divided by negative two raised to the second power is negative two raised to the sixth power divided by negative two raised to the fourth power; option D.
<h3>What is a mathematical expression?</h3>
A mathematical expression is an expression which uses mathematical symbols and mathematical operations to represent an idea.
Two mathematical expressions are equivalent if they have the same value
The expression that is equivalent to negative two raised to the fourth power divided by negative two raised to the second power can be written as (-2)⁴/(-2)² = 2²
An equivalent expression is negative two raised to the sixth power divided by negative two raised to the fourth power written as : (-2)⁶/(-2)⁴ = 2²
In conclusion, two mathematical expressions are equivalent if they have the same value when fully expressed.
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Answer:
It intersects the x-axis at x = 10
Step-by-step explanation:
Step 1: Find slope <em>m</em>
m = (5 - 1)/(5 - 9)
m = 4/-4
m = -1
y = -x + b
Step 2: Find <em>b</em>
5 = -5 + b
b = 10
Step 3: Rewrite equation
y = -x + 10
Step 4: Find <em>x</em> when <em>y</em> = 0
0 = -x + 10
-10 = -x
x = 10
So the graph crosses the x-axis at 10.
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function 
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
To prove that triangles TRS and SUT are congruent we can follow these statements:
1.- SR is perpendicular to RT: Given
2.-TU is perpendicular to US: Given
3.-Angle STR is congruent with angle TSU: Given.
4.-Reflexive property over ST: ST is congruent with itself (ST = ST)
From here, we can see that both triangles TRS and SUT have one angle of 90 degrees, another angle that they both have, and also they share one side (ST) ,then:
5.- By the ASA postulate (angle side angle), triangles TRS and SUT are congruent
