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4 years ago

Which of the following pairs of organisms compete with each other for food?

Mathematics

2 answers:

erastovalidia [21]4 years ago

8 0

The answer would be D. Mice and Rabbits. Hope it helps! :)

Natasha_Volkova [10]4 years ago

8 0

Its gotta be D. mice and rabbits, hope this helps. :))

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Use a cofunction identity to rewrite cos(120° − (30° + a)).

elena55 [62]

Answer:

sina

Step-by-step explanation:

Using the cofunction identity

cos(90 - x) = sinx , then

cos(120 - (30 + a) )

= cos(120 - 30 - a)

= cos(90 - a)

= sina

5 0

4 years ago

When graphing inequalities why do you use closed or open dot?

miv72 [106K]

To let u know if it is either equal to or not

8 0

3 years ago

Which type of parent function does the equation f (x) = a represent?

sweet [91]

I think it’s C, I’m not sure tho so sorry if I get it wrong :(

5 0

3 years ago

What is the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compare

Elena-2011 [213]

Answer:

38.9 square inches.

Step-by-step explanation:

We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.

We will use area of sector formula to solve our given problem as:

$\text{Area of sector}=\frac{\theta}{360}\times \pi r^2$ , where, r represents radius and theta represents central angle.

Let us find area of sector with central angle 140 degree and radius 3 inch.

$\text{Area of sector}=\frac{138}{360}\times \pi (3)^2$

$\text{Area of sector}=\frac{138}{360}\times 9\pi$

$\text{Area of sector}=10.83849$

Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:

$\text{Area of sector}=2(\frac{114}{360}\times \pi (5)^2)$

$\text{Area of sector}=2(\frac{114}{360}\times 25\pi)$

$\text{Area of sector}=\frac{114}{360}\times 50\pi$

$\text{Area of sector}=49.74188$

Let us find difference of area as shown below:

$\text{Difference of areas}=49.74188-10.83849$

$\text{Difference of areas}=38.90339$

$\text{Difference of areas}\approx 38.9$

Therefore, the difference in area covered is approximately 38.9 square inches.

8 0

3 years ago

The water level of a lake has been increasing each year. The initial water level of the lake was 800 meters, and the water level

ivanzaharov [21]

2x=5x1800+1500(56-7)

7 0

4 years ago