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Furkat [3]
4 years ago
6

Which of the following pairs of organisms compete with each other for food?

Mathematics
2 answers:
erastovalidia [21]4 years ago
8 0
The answer would be D. Mice and Rabbits. Hope it helps! :)
Natasha_Volkova [10]4 years ago
8 0
Its gotta be D. mice and rabbits, hope this helps. :))
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Use a cofunction identity to rewrite cos(120° − (30° + a)).
elena55 [62]

Answer:

sina

Step-by-step explanation:

Using the cofunction identity

cos(90 - x) = sinx , then

cos(120 - (30 + a) )

= cos(120 - 30 - a)

= cos(90 - a)

= sina

5 0
4 years ago
When graphing inequalities why do you use closed or open dot?
miv72 [106K]
To let u know if it is either equal to or not
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3 years ago
Which type of parent function does the equation f (x) = a represent?
sweet [91]
I think it’s C, I’m not sure tho so sorry if I get it wrong :(
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3 years ago
What is the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compare
Elena-2011 [213]

Answer:

38.9 square inches.

Step-by-step explanation:

We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.

We will use area of sector formula to solve our given problem as:

\text{Area of sector}=\frac{\theta}{360}\times \pi r^2, where, r represents radius and theta represents central angle.

Let us find area of sector with central angle 140 degree and radius 3 inch.

\text{Area of sector}=\frac{138}{360}\times \pi (3)^2

\text{Area of sector}=\frac{138}{360}\times 9\pi

\text{Area of sector}=10.83849

Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:

\text{Area of sector}=2(\frac{114}{360}\times \pi (5)^2)

\text{Area of sector}=2(\frac{114}{360}\times 25\pi)

\text{Area of sector}=\frac{114}{360}\times 50\pi

\text{Area of sector}=49.74188

Let us find difference of area as shown below:

\text{Difference of areas}=49.74188-10.83849

\text{Difference of areas}=38.90339

\text{Difference of areas}\approx 38.9

Therefore, the difference in area covered is approximately 38.9 square inches.

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3 years ago
The water level of a lake has been increasing each year. The initial water level of the lake was 800 meters, and the water level
ivanzaharov [21]
2x=5x1800+1500(56-7)
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