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Shalnov [3]
3 years ago
7

The following image is a function.

Mathematics
1 answer:
Alborosie3 years ago
6 0
That is going to be false
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Solve the system of the linear equation using any method:<br> 2x+5y=4<br> 4x+7y=11
mr_godi [17]
Multiply the first equation by 2:
4x+10y=8
Subtract the second equation from this so the 4x cancels:
3y = -3
y = -1
Plug into first equation:
2x -5 = 4
2x = 9
x = 9/2 = 4 1/2 = 4.5
So (x,y) = (-1,4.5)
3 0
3 years ago
Read 2 more answers
How much money has to be invested at 5.9% interest compounded continuously to have $15,000 after 12 years?
scoray [572]

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

Step-by-step explanation:

The given is,

                Future value, F  = $15,000

                           Interest, i = 5.9%

              ( compounded continuously )

                            Period, t = 12 years

Step:1

           Formula to calculate the present with compounded continuously,

                                       F=Pe^{(i)(t)}...............(1)

           Substitute the values in equation (1) to find the P value,

                                  15000=Pe^{(0.059)(12)}          ( ∵ i = \frac{5.9}{100}=0.059 )

                                  15000=Pe^{0.708}

                                  15000=P(2.0299)             ( ∵ e^{o.708} =2.0299 )

            We change the P (Present value) into the left side,

                                        P=\frac{15000}{2.0299}

                                            =7389.427

                                            ≅ 7389.43

                                         P = $ 7389.43

Result:

           The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.  

                       

8 0
3 years ago
Which ordered pair is a solution of the equation -3x - y = 6
e-lub [12.9K]
Hello there!


The correct answer is option B (-3,3)

-3x - y = 6

-3(-3) - 3 = 6

9 - 3 = 6

6 = 6

Thus, the correct answer is option B

Good luck with your studied!


8 0
3 years ago
Divide 20m^2n^3 - 10m^2n by 5mn
Sonja [21]

\frac{20 {m}^{2} {n}^{3}  - 10 {m}^{2}n  }{5mn}  \\  =   \frac{5mn(4m {n}^{2} - 2m) }{5mn}  \\  = 4 {m}^{2} n - 2m \\  = 2m(2mn - 1)

Hope this helps. - M
6 0
3 years ago
For a horizontal launch (θ0 = 0) at a fixed height ℎi &gt; 0, are the statements below correct? (Assuming friction can be ignore
Marizza181 [45]

Answer:

1) False. 2) True. 3) True. 4) False.

Step-by-step explanation:

1) False. The force of gravity will drive it down. The path will form a parabola.

2) True. There is no variation in the velocity in the horizontal axis and no force applied so the acceleration is zero.

3) True. The travel time depends on the height and the acceleration of gravity, and independent of the velocity of the rocket at launch.

4) False. The travel distance depends on the initial velocity of the rocket (at launch).

5 0
3 years ago
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