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3 years ago

15

Select the system of linear inequalities whose solution is graphed.

1 answer:

elixir [45]3 years ago

5 0

Answer:

$y\geq 3x-1$ ; $x+3y\leq 6$

Step-by-step explanation:

we know that

step 1

Find the inequality of the solid line x+3y=6

The solution is the shaded area below the solid line

therefore

The equation of the inequality is

$x+3y\leq 6$

step 2

Find the inequality of the solid line y=3x-1

The solution is the shaded area above the solid line

therefore

The equation of the inequality is

$y\geq 3x-1$

therefore

The system of linear inequalities is

$y\geq 3x-1$ ; $x+3y\leq 6$

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Natasha_Volkova [10]

$f(x)=25(4)^{\frac{x}{2}}$ will be the function to calculate population every half year.

Further explanation:

The given formula is:

$f(x) = 25(4)^x$

In the given formula, x represents the amount of time in years. So, in order to convert the given function for yearly calculation of population, to find the population every half year the time will be converted into half. This means that instead of x, x/2 will be used.

So the new function will be:

$f(x) = 25(4)^{\frac{x}{2}}$

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Gnom [1K]

Your answer will be 45. Hope this helps!

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3 years ago

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aksik [14]

Area of the large semicircle

$= \pi{r}^{2} \div 2$

$= \frac{22}{7} \times 12 {}^{2} \times \frac{1}{2}$

$= \frac{11}{7} \times12 \times 12$

$= \frac{11}{7} \times 144$

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Area of the small semicircle

$= \pi {r}^{2} \div 2$

$= \frac{22}{7} \times 6 {}^{2} \times \frac{1}{2}$

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pashok25 [27]

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The slope of a function is equal to

$\frac{f(x_2)-f(x_1)}{x_2-x_1}$

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$m=\frac{10--2}{-9--1}\\m=\frac{12}{-8}\\m=-\frac{3}{2}$

So the slope is -3/2

Now we can use point-slope form.

Point slope form is represented by

$Y-Y_1=m(X-X_1)$

So when we plug in our values we get

$Y--2=-3/2(X--1)\\Y+2 = -3/2(X+1)\\Y+2 = -3/2X-3/2\\Y=-3/2X-7/2$

So the equation is

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3 years ago

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Answer:

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