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shepuryov [24]
3 years ago
14

Order the numbers from least to greatest. 1=least and 4=greatest

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

\sqrt{\frac{9}{4}}       \frac{5}{3}         \sqrt{5}       2.5

Step-by-step explanation:

Given

\sqrt{\frac{9}{4}}

\sqrt{5}

2.5

\frac{5}{3}

Required

Order from least to greatest

<em>Start by simplifying each expression</em>

\sqrt{\frac{9}{4}}

Split square root

\frac{\sqrt{9}}{\sqrt{4}}

Take square root of numerator and denominator

\frac{3}{2}

1.5

Hence

\sqrt{\frac{9}{4}} = 1.5

-----------------------------------------------------------

\sqrt{5}

\sqrt{5} = 2.2361 (Approximated)

-----------------------------------------------------------

2.5

-----------------------------------------------------------

\frac{5}{3}

\frac{5}{3} = 1.6667

Considering the simplified expression; the number from least to greatest is:

\sqrt{\frac{9}{4}}       \frac{5}{3}         \sqrt{5}       2.5

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Solve the following 3 × 3 system. Enter the coordinates of the solution below.
love history [14]
The system is:

i)    <span>2x – 3y – 2z = 4
ii)    </span><span>x + 3y + 2z = –7
</span>iii)   <span>–4x – 4y – 2z = 10 

the last equation can be simplified, by dividing by -2, 

thus we have:

</span>i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7
iii)   2x +2y +z = -5 


The procedure to solve the system is as follows:

first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:

i)    2x – 3y – 2z = 4   
iii)   2x +2y +z = -5 

2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.

Equalize:  

3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9   

similarly, using i and ii, eliminate x:

i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7

multiply the second equation by 2:


i)    2x – 3y – 2z = 4
ii)    2x + 6y + 4z = –14

thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:

3y+2z+4=-6y-4z-14
9y+6z=-18

So we get 2 equations with variables y and z:

a)   5y+3z=-9 
b)   9y+6z=-18

now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.

Let's use elimination method, multiply the equation a by -2:

a)   -10y-6z=18 
b)   9y+6z=-18
------------------------    add the equations:

-10y+9y-6z+6z=18-18
-y=0
y=0,

thus :
9y+6z=-18 
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z=-3

Finally to find x, use any of the equations i, ii or iii:

<span>2x – 3y – 2z = 4 
</span>
<span>2x – 3*0 – 2(-3) = 4

2x+6=4

2x=-2

x=-1

Solution: (x, y, z) = (-1, 0, -3 ) 


Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:

check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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