Answer:
Assuming the dominant allele is represented as A, and the genotype as AA and the recessive as a, and genotype as aa; then the F1 will produce the offispring. Aa, Aa, Aa,Aa in ratio: 1:1:1:1:1
This shows the dominance of allele A.
However if two of the F1 generation are crossed then:
The F2 is AA,Aa,Aa,aa the phenotypic ratio is
3 ; 1
W<u>hile the Genotypic ratio is ratio;</u>
<u> 1AA : 2Aa Aa; 1aa(1 ;2;1)</u>
Explanation:
Answer:
The correct answer is A. The region of the diencephalon that is responsible for maintaining homeostasis is the hypothalamus.
Explanation:
One of the main functions of the hypothalamus is to control the pituitary gland, an endocrine gland that participates in the regulation of various functions of the organism, many of them related to homeostasis (regulation of glycemia, osmolarity, etc).
Answer:
His phenotype would be having dry earwax
Explanation:
<h2>Frequency of allele </h2>
Explanation:
Hardy Weinberg Equilibrium is used to calculate the allelic as well as genotypic frequency
Allelic frequency of dominant and recessive allele is represented by p and q respectively whereas genotypic frequency of dominant genotype is represented by
and
respectively
Given:
H allele (p) = hairy heffalump (dominant)
h allele (q) = hairless heffalump (recessive)
36% of heffalump population is hairless represents the % of recessive genotype, hh (
) =36%
Calculation of frequency of the h allele (q) :
Frequency of genotype hh (
) will be: 36/100=0.36 or 0.6*0.6
Frequency of h allele (q) will be 0.6
Answer:
2,855 is the size of the colony of mosquitoes after 4 days.
Explanation:
The law of uninhibited growth is given as:

= Original amount
A = Amount after time t
k = Positive constant repressing the rate of growth
We are given with:
Original population of mosquitoes = 1000
Population of mosquitoes after 1 day =1300
t = 1 day


Population size of mosquitoes after 4 days

A =? , t = 4 days

A =2,855.36 ≈ 2,855 mosquitoes
2,855 is the size of the colony of mosquitoes after 4 days.