Write a Lewis structure that obeys the octet rule for SOCl2 (S is the central atom) and assign formal charges to each atom. Draw
the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons and formal charges.
1 answer:
Answer : The Lewis-dot structure of is shown below.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is,
As we know that sulfur has '6' valence electrons, chlorine has '7' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 6 + 6 + 2(7) = 26
According to Lewis-dot structure, there are 8 number of bonding electrons and 18 number of non-bonding electrons.
Now we have to determine the formal charge for each atom.
Formula for formal charge :
Hence, the Lewis-dot structure of is shown below.
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Answer:
1.345*10⁻⁴ mol/L
15.023 mg/L
Explanation:
The chemical <u>formula of ferrocene</u> is Fe(C₅H₅)₂, thus its molecular weight is:
55.845 g/mol + 10*12g/mol + 10 *1g/mol = 185.845 g/mol
- The moles of Fe contained in 25 mg (or 0.025 g) of ferrocene are:
- The final volume is 500 mL, or 0.5 L. So the iron concentration in mol/L is:
- We can convert that value into mg/L:
The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).
Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.
We can use the following equation to calculate the volume of more concentrated solution required:
where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).
Applying the values given by the question to the equation above, we'll have:
Thus, we would need 5.00 mL of the more concentrated solution.
Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:
Thus, we would need 45.0 mL of water to prepare the solution.
Therefore, we can complete the sentence given as:
<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>