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timofeeve [1]
3 years ago
10

A scientist who is trying to develop a material that is soft and malleable and also conducts electricity will likely use a__

Chemistry
1 answer:
Sonbull [250]3 years ago
6 0
It's A, metals. Metals are solid at room temperature but still very malleable and the best conductors. Metalloids can still conduct electricity but nowhere near as well as metals. 
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36. Dimensional Analysis: A useful way to convert units using multiplication & division *Always start with what you are give
ollegr [7]

Answer:

A) 7.9 x 10⁶ inches

B) 1004 g

C) 2.8 x 10³ inches/ min

D) 1.2 x 10⁻⁴ mm

Explanation:

A) Since 39.37 inches = 1 m, you can convert meters to inches by multiplying by the conversion factor (39.37 inches /  1 m).

Notice that if 39.37 inches = 1 m then 39.37 inches / 1 m = 1. That means that when you multiply by a conversion factor, you are only changing units since it is the same as multiplying by 1 :

2.0 x 10⁵ m * (39.37 inches /  1 m) = 7.9 x 10⁶ inches

B) Conversion factors : (2.205 pounds / 1 kg) and (453.59 g / 1 pound), because 2.205 pounds = 1 kg and 1 pound = 453.59 g. Then:

1.004 kg * ( 2.205 pounds / 1 kg) * ( 453.59 g / 1 pound) = 1004 g

C) Conversion factor: (39.37 inches / 1 m) and (60 s / 1 min)

1.2 m/s * (39.37 inches / 1 m) * ( 60 s / 1 min) = 2.8 x 10³ inches/ min

D)Converison factor ( 1 mm / 1 x 10⁶ nm):

120 nm (1 mm /  1 x 10⁶ nm) = 1.2 x 10⁻⁴ mm

3 0
3 years ago
Read 2 more answers
To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance.
kap26 [50]

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

In spectrophotometry, to plot the calibration curve, you need to prepare solutions with known concentrations and measure their absorbance.

We have a standard iron solution with a concentration of 0.2500g/L of pure iron (C₁). We pipet 25.00mL (V₁) of this standard iron solution into a 500mL (V₂) volumetric flask and dilute up to the mark with distilled water.

We can calculate the concentration of the diluted solution (C₂) using the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\\\C_2 = \frac{C_1 \times V_1}{V_2}  = \frac{0.2500 g/L \times 25.00 mL}{500 mL} = 0.0125 g/L

Then, if we wanted to prepare the blank, that is, the solution that contains the same matrix but not the analyte, and whose concentration in iron is 0.00 mg/L, we wouldn't pipet any of the diluted solution.

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

Learn  more: brainly.com/question/24195565

8 0
3 years ago
How do the products of chemical reactions compare to their reactants?
Ket [755]

The products of chemical reactions often have completely different properties than the reactants, like viscosity, boiling and melting temperatures, etc.

That is because the atoms form new and different bonds to give the products.

8 0
1 year ago
What is the charge on an electron? –1 0 +1 +2
Maurinko [17]

Answer: -1

Explanation:

7 0
3 years ago
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Of the metals pb hg na and mg which will not spontaneously donate electrons to copper in solution
marta [7]

Answer : Hg (Mercury)


Explanation : In the given series of elements Na falls after the Cu in the reactivity series, for Pb it also falls after Cu, and for Mg it is the same.


Only Hg which is mercury can spontaneously donate its electrons to copper in the solution because it falls before Cu in the reactivity/activity series.

3 0
3 years ago
Read 2 more answers
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