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Paha777 [63]
3 years ago
11

Finn is baking cakes for a party. The number of cups of sugar Finn needs is proportional to the number of cakes he plans to bak

e. Which statements are true about the number of cups of sugar Finn needs?
Select each correct answer.
Finn needs 6 cups of sugar for 4 cakes.
Finn needs 1 cup of sugar for 1 1/2 cakes.
Finn needs 4 cups of sugar for 6 cakes.
Finn needs 1 1/2 cups of sugar for 1 cake.

Mathematics
2 answers:
levacccp [35]3 years ago
4 0

Answer:

Finn needs 6 cups of sugar for 4 cakes, and Finn needs 1 1/2 cups of sugar for 1 cake.

Step-by-step explanation:

On the graph, we go over to 4 cakes along the independent axis.  We go up to the line to see that the line goes through the point (4, 6).  

On the graph, we go over to 1 1/2 cakes along the independent axis.  We go up to the line to see that the line goes through the point (1 1/2, 2).  This is not the point (1 1/2, 1).

On the graph, we go over to 6 cakes along the independent axis.  We go up to the line to see that the line goes through the point (6, 9).  This is not the point (6, 4).

On the graph we go over to 1 cake along the independent axis.  We go up to the line to see that the line goes through the point (1, 1/2).

pishuonlain [190]3 years ago
3 0
1st and 4th answers are correct.
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In a class 28 of students, 5 are female and 19 have an A in the class. There are 2 students who are female and have an A in the
telo118 [61]

Step-by-step explanation:

Of the 28 students, 5 are female.  So the probability is 5/28.

5 0
3 years ago
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
3 years ago
FIND THE UNIT RATE AND ROUND TO THE NEAREST HUNDREDTHS IF NECESSARY. Jasigreen's class opened last year and serviced 6,840 custo
Vladimir [108]
<span>6840 customers ... 45 days<span>
x customers = ? ... 1 day

If you would like to know how many customers were in Jasigreen's class in 1 day, you can calculate this using the following steps:

6840 * 1 = 45 * x
6840 = 45 * x     /45
x = 6840 / 45
x = 152 customers

<span>The correct result would be </span>152 customers<span>.</span></span></span>
4 0
3 years ago
(image is question) ................................
Nimfa-mama [501]

Answer:

2x^2

Step-by-step explanation:

If you're going to double x^2, you just need to multiply it by 2. You can just put the 2 in front of the x^2 because the order of operations says to do exponents before multiplication.

6 0
2 years ago
Midsegment of triangle <br> Find X
Charra [1.4K]

Answer:

10 = x

Step-by-step explanation:

This is what is called the Midsegment Theorem, which states that the relation of a triangle's midpunkt is parallel to the triangle's third side, and the mid-segment length is half the third side length, so you would take half of 4x + 20 and set that expression equal to the midsegment:

2x + 10 = 3x

-2x - 2x

____________

10 = x

You then plug this back into both expressions above to get the double-segment of 60 and the mid-segment of 30. We can tell this is correct because 30 and 60 are relatively proportional to each other.

I am joyous to assist you anytime.

4 0
3 years ago
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