Answer:
its blurry
Step-by-step explanation:
Answer:
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.


The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.
The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Answer:
17.7
Step-by-step explanation:
<em>First off, we do not need to do anything to the 17, it is already set up for a decimal. So we have to find out how much 1/50 is so we divide:</em>
<u>Divide:</u>
1/50=0.02
<u>Multiply by 35:</u>
0.02 times 35= 0.7
<u>Add the 17:</u>
17+0.7=<em><u>17.7</u></em>
I hope this helps u pls give a brainliest and a thx ;)
leave a comment if i am wrong