2 years ago

Using the rule y = 3x + 4, find the value of y when x is 2.

2 answers:

8 0

The answer is 10.
Here's why:
The equation that we have is y=3x+4 , we know the value of x , but not the value of y.
If x=2 , the new equation is:
y=3(2) + 4
3(2)= 6 + 4=10
The answer is 10 which means that B is correct.

andrew-mc [135]2 years ago

3 0

Equation:y=3x+4. Given x=2
y=3(2)+4
y=6+4
y=10
Answer is B.

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Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.

Naya [18.7K]

It's a geometric sequence.

$4,-12,36,... \\ \\
a_1=4 \\
r=\frac{a_2}{a_1}=\frac{-12}{4}=-3 \\ \\
a_n=a_1 \times r^{n-1} \\
a_n=4 \times (-3)^{n-1} \\
a_n=4 \times (-3)^{-1} \times (-3)^n \\
a_n=4 \times (-\frac{1}{3}) \times (-3)^n \\
a_n=-\frac{4}{3}(-3)^n$

It's the sum for term 4 through term 15.

$\boxed{ \sum\limits_{n=4}^{15} (\frac{4}{3}(-3)^n)}$

8 0

2 years ago

In order to determine the average weight of carry-on luggage by passengers in airplanes, a sample of 25 pieces of carry-on lugga

Fynjy0 [20]

To find the standard error, divide the standard deviation by the square root of the sample size

standard deviation = 7.5
sample size = 25......sqrt 25 = 5

standard error = 7.5 / 5 = 1.5 <==

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B5%7D%2B%5Cfrac%7B3x%7D%7B15%7D%3D%5Cfrac%7B2x%7D%7B3%7D%20%7D%20" id="TexF

Bezzdna [24]

Multiply all terms by 15
3x+3x= 10x+30

Combine like terms
6x=10x+30

Subtract 10x from both sides
-4x=30

Divide both sides by -4
x= -7.5

Final answer: -7.5

4 0

2 years ago

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

4 0

2 years ago

5 1⁄2 × 3 3⁄5 × 1 1⁄3

gayaneshka [121]

The answer should be 3/2 or 1.5

Hope this helps!

7 0

2 years ago

Read 2 more answers