All categories

3 years ago

[(14 + 7) divided by 3] + 10 • (6-3) Answer here

Mathematics

1 answer:

mixer [17]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path. which number line cor

Fynjy0 [20]

Given :

A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path.

To Find :

Which number line correctly models this situation and the total number of distance markers.

Solution :

It is given that their are markers every 1/4 part of mile.

So, their are 4 markers per mile.

Numbers of markers in 3 miles long path is :

$n = 3\times 4\\\\n = 12$

Therefore, the total number of distance markers in 3 mile path is 12.

Hence, this is the required solution.

5 0

3 years ago

8n - (2n+11 - 54)<br>simplify

Serjik [45]

Answer:

8n - (2n + 11 - 54) =

Step-by-step explanation:

6n + 43, I used a calculator !

5 0

2 years ago

Find the points on the cone z2 = x2 + y2 that are closest to the point (6, 2, 0).

aliya0001 [1]

Answer:

The closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

Step-by-step explanation:

Let B(x, y, z) denote a point on the cone.

Therefore, the distance between the points (6, 2, 0) and B(x, y, z) is;

d = √[(x - 6)² + (y - 2)² + (z - 0)²]

d = √[(x - 6)² + (y - 2)² + z²]

Since we are given that z² = x² + y², we now have;

d = √[(x - 6)² + (y - 2)² + x² + y²]

Taking the square of both sides gives;

d² = [(x - 6)² + (y - 2)² + x² + y²]

x² is an increasing function. Thus, minimizing d is also the same as to minimize f (x, y) = d²

Thus, f' = 0. So;

df/dx = 2(x - 6) + 2x = 0

2x - 12 + 2x = 0

4x = 12

x = 12/4

x = 3

Similarly,

df/dy = 2(y - 2) + 2y = 0

2y - 4 + 2y = 0

4y - 4 = 0

4y = 4

y = 4/4

y = 1

Now,from earlier;

z² = x² + y²

Thus;

z = ±√(3² + 1²)

z = ±√10

Thus, the closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

7 0

3 years ago

Evaluate s(t)=∫t−[infinity]||r′(u)||du for the bernoulli spiral r(t)=⟨etcos(8t),etsin(8t)⟩. It is convenient to take −[infinity]

sveta [45]

$\vec r(t)=\langle e^t\cos8t,e^t\sin8t\rangle$

$\|\vec r'(t)\|=\sqrt{(e^t(\cos8t-8\sin8t))^2+(e^t(\sin8t+8\cos8t))^2}=e^t\sqrt{(\cos8t-8\sin8t)^2+(\sin8t+8\cos8t)^2}$

$\implies\|\vec r'(t)\|=e^t\sqrt{65}$

Then

$s(t)=\displaystyle\sqrt{65}\int_{-\infty}^te^u\,\mathrm du=\sqrt{65}e^t$

3 0

3 years ago

brainly is the best app in the whole world) sam has 5 dollars he works for 5 hours and he earns 900 dollars and hour how much mo

saveliy_v [14]

Answer:

Sam has $900 more money. In total he now has $905.

5 0

2 years ago