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Elza [17]
3 years ago
15

Shape A can be transformed to shape B by a reflection in the x-axis followed by a translation (c/d). Find the value of c and the

value of d
Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

c = -6

d = -1

Step-by-step explanation:

Given

See attachment for grid

Required

Find c and d

From the attachment, we have:

a = (3,5) --- Point on A

a' = (-3,-6) --- Corresponding point on B

When A is reflected across the x-axis, the rule is:

(x,y) \to (x,-y)

So, we have:

(3,5) \to (3,-5)

Next, is to calculate the translation from (3,-5) to (-3,-6)

This is calculated using:

3 + c = -3

and

-5 + d = -6

So, we have:

3 + c = -3

c = -3-3

---- i.e. Shift by 6 units to the left

-5 + d = -6

d = 5 - 6

d = -1  --- i.e. Shift by 1 unit down

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4 pounds = $1.96
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3 years ago
Question 1,2, and 3 how do i factor those? Can you show the work and explain how?
DiKsa [7]

1: 3n^{2}+9n+6

notice that each part is divisible by 3

3n^{2} ÷ 3 = n^{2}

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes 3(n^{2} +3n+2)

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

3(n^{2} +2n+n+2)

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is n^{2} +2n+n+2 and then each of those by 3, which is 3n^{2} +6n+3n+6 or 3n^{2}+9n+6, our origional equation

2: 28+x^{2} -11x

So I rewrote this as x^{2} -11x+28 (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

x^{2} -4x-7x+28

now we can factor out x from the first expression and -7 from the second

x(x-4)-7(x-4)

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to x^{2} -11x+28

3: 9x^{2} -12x+4

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as 3^{2} and 4 as 2^{2}, the equation becomes

3^{2} x^{2} -12x+2^{2}

now that 3^{2} x^{2} is ugly so it can be turned into (3x)^{2}

and -12x can be rewritten as -2*3x*2

so our equation now looks like (3x)^2-2*3x*2+2^{2}

There's a rule that says a^{2} -2ab+b^{2} = (a-b)^{2}

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

(3x-2)^2

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Step-by-step explanation:

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Please Help practice #3
algol [13]

Answer:

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Step-by-step explanation:

Given the expression 8x^2 + 26x + 15

Factorize

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= 2x(4x+3) + 5 (4x+3)

= (2x+5)(4x+3)

Hence the factored form of the expression is (2x+5)(4x+3)

5 0
3 years ago
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