Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
I'm pretty sure it's graph A. I apologize if it's wrong hope this helped.
Answer:
£18
Step-by-step explanation:
Let
x = original price of the game
Increase in price = 1/2
New price = £27
x + 1/2x = £27
2x+x/2 = 27
3/2x = 27
x = 27 ÷ 3/2
= 27 × 2/3
= 54 / 3
x = £18
Therefore, the original price of the game is £18
The sin <ABC means that AC/AB. So we know AB=34. AC/AB=8/17. So the length of AC is 16. cos<ABC means BC/AB. tan<ABC means AC/BC.
16 * 3 = 48
and
16 + 3 = 19
