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2 years ago

Whoops i was confused a bit with the answers this is the same as the last one

Mathematics

1 answer:

Vikentia [17]2 years ago

7 0

Answer:

start from smallest to biggest going down the line

Step-by-step explanation:

its quite easy once you know which is biggest and which is smallest

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Solve for x: (1/2) + 4/(2x) = (x + 4)/10

Charra [1.4K]

Answer:

x = 5 , − 4

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable x .

8 0

3 years ago

What is the value of y?

mojhsa [17]

<h2>QUESTION:- What is the value of y?</h2>

<h2>ANSWER:- </h2>

SUM OF ALL INTERIOR ANGLE = 180

$y + y + 72 = 180 \\ 2y + 72 = 180 \\ 2y = 180 - 72 \\ 2y = 108 \\ y = \frac{108}{2} \\ y = \frac{ \cancel{108}^{ \: \: \: \tiny{54}} }{ \cancel{2}} \\ y = 54 \degree$

4 0

3 years ago

Read 2 more answers

Assignment: Translating Functions Investigation

Leto [7]

Answer:

Part A)

1) The graph in the attached figure N 1

2) The coordinate rule is (x,y) -----> (x,y+10)

3) The translation of the function up 10 units means that the initial deposit is $60 instead of $50

Part B)

1) The graph in the attached figure N2

2) The coordinate rule is (x,y) -----> (x-10,y)

3) The translation of the function right 10 units means that the initial deposit is equal to $10

Part C)

1) In each translation, the slope is the same (m=5) are parallel lines

2) The vertical translation would be up 40 units

Step-by-step explanation:

we have

$f(x)=5x+50$

where

f(x) --> represents Jeremy's account balance

x ---> the time in years

Part A)

The translation of the function is up 10 units.

The rule of the translation is equal to

(x,y) -----> (x,y+10)

The new function will be

$f(x)=5x+50+10$

$f(x)=5x+60$

The graph in the attached figure N 1

The translation of the function up 10 units means that the initial deposit is $60 instead of $50

Part B)

The translation of the function is right 10 units.

The rule of the translation is equal to

(x,y) -----> (x-10,y)

we have

$f(x)=5x+60$ ----> function Part A

The new function will be

$f(x)=5(x-10)+60$

$f(x)=5x+10$

The graph in the attached figure N 2

The translation of the function right 10 units means that the initial deposit is equal to $10

Part C)

1. Look at the translations, what characteristic of the graph stayed the same in each translation?

In each translation, the slope is the same

The slope m is equal to m=5

Are parallel lines

2. Look at the original graph and the graph of the translation right 10 units. What vertical translation of the graph in Part B would put the graph back to its original position?

we have

$f(x)=5x+10$

The vertical translation would be up 40 units

The rule of the translation is equal to

(x,y) -----> (x,y+40)

The new function will be

$f(x)=5x+10+40$

$f(x)=5x+50$

3 0

3 years ago

1. Use the image of the circle to identify the length of the radius, diameter, and circumference. Leave all answers in terms of

Grace [21]

Answer:

Radius = r = 7.5

Diameter = d = 15

Circumference = C = 15π

Step-by-step explanation:

We are given the image of a circle with a straight line passing through the center of the circle and touching its edges. Such a line is known as the diameter of the circle. From the image we can see the length of the diameter of the circle is d = 15 units.

Radius is define as half of the diameter. Since the diameter is 15 units, the radius of the given circle will be half of 15 which is r = 7.5 units.

Circumference of the circle = C = 2πr

Using the value of radius(r), we can write the circumference as:

C = 2π(7.5) = 15π

5 0

2 years ago

Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0

Snowcat [4.5K]

Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

$\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\$

Let the value a so, the value of $a_n$ and the value of $a_(n+1)$ is:

$\to a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}$

$\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}$

To calculates its series we divide the above value:

$\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\$

$= \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\$

$= \frac{x^2}{2^2(n+1)^2}\longrightarrow 0$ for all x

The final value of the converges series for all x.

8 0

3 years ago