Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
Step-by-step explanation:
First;
x to third power=x³
y to 4th power=y⁴
<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>c</u><u>o</u><u>n</u><u>d</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u>
expression=x³ × y⁴
=x³y⁴
Answer: A/The LINE graph
Step-by-step explanation:
Answer:
you can find angle E by
Step-by-step explanation:
sum of angles of traingle is 180 degree
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Answer:
x = 22.5°
Step-by-step explanation:
Angle BED ≅ angle EBC = 6x, so angle BEA = 4x. The angles FEB and BEA form a linear pair, so we have ...
4x +4x = 180°
x = 22.5° . . . . . . divide by 8
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BED and EBC are "alternate interior angles" with respect to transversal BE crossing parallel lines DE and AC.