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Hatshy [7]
3 years ago
11

Highway patrol officers measure the speed of automobiles on a highway using radar equipment. The random variable in this experim

ent is speed, measured in miles per hour. This random variable is a _____. a. discrete random variable b. continuous random variable c. complex random variable d. None of the answers is correct.
Mathematics
1 answer:
Nastasia [14]3 years ago
8 0

Answer:

b. continuous random variable

Step-by-step explanation:

Speed is a common continuous variable and the value is always random.

It is continuous because there is always another speed value between two speed values. For example, a car travelling at the rate of 50 mils per hour will either increase or decrease its speed at a continuous rate. No speed can drop suddenly form 50mph to 20mph.

It is random because although there might be speed limit, the speed recorded by the Highway patrol officer willl always be random in value.

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The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a
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Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
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So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
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2x   - 3y  +  z = 0

<h3>Case-3:</h3>
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therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

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Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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