Find the z-scores for the two scores in the given interval.

For the score x =391,

.
For the score x = 486,

Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.
The decrease is 35c
Q= X/100 of $1.37 = 0.35
1.37x/100 = 0.35
1.37x = 35 then divide each side by 1.37
Result is 25.5474453 percent, round up to nearest tenth.
Answer is 25%
I think they are similar because they are both solving for a certain number (sum, product quotient)
Step-by-step explanation:
1) y = -x+4
2) y-4= -2(x-3)
y = -2x+6+4
y = -2x+10
3) slope = (3+1)/(9-1) = 4/8=½
the Equation =>
y+1= ½(x-1)
y = ½x -½-1
y = ½x - 1½ or 2y = x -3
Angle 1 = 4x - 16
angle 2 = 2x + 10
4x - 16 + 2x + 10 = 90
combine like terms
6x - 6 = 90
add 6 to both sides
6x = 96
divide both sides by 6
x = 16
angle 1 = 4x - 16 = 4(16) - 16 = 48
angle 2 = 2x + 10 = 2(16) + 10 = 42