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marshall27 [118]
3 years ago
9

Which statement accurately describes the two congruent triangles

Mathematics
1 answer:
inessss [21]3 years ago
3 0
What are the statements and what do the triangles look like?
You might be interested in
How do I solve and find x for this question
Fed [463]

Answer: -9.1


Explanation
-3x +12.4=39.7
First minus 12.4 from both sides

-3x +12.4=39.7
-12.4 -12.4
-3x=27.3
Now devid both sides by -3
X= -9.1
7 0
2 years ago
Your friend attempted to factor an expression as shown. Find the error in your friends work. Then factor the expression correctl
loris [4]

Answer:

Third step is incorrect. The correct factored form is (x-1)(2x-5).

Step-by-step explanation:

The given expression is

2x^2-7x+5

We need to find the factored form of this expression.

Step 1: Given

2x^2-7x+5

Step 2: Splitting the middle term method, the middle term can be written as (-5x-2x).

2x^2-5x-2x+5

(2x^2-5x)+(-2x+5)

Step 3: Taking out common factors from each parenthesis.

x(2x-5)-1(2x-5)

Step 4: Taking out common factors.

(x-1)(2x-5)

Therefore, the third step is incorrect. The correct factored form is (x-1)(2x-5).

3 0
3 years ago
Find the measure of the missing angle *
lubasha [3.4K]

Answer:

21°

Step-by-step explanation:

we know that every single triangle has to equal 180°

we have all 3 angles 90° 34° 35° which equal 159°

so we take 180°-159° and your answer is 21°

6 0
3 years ago
PLS ANSWER FAST I NEED IT ASAP find the coordinates of p so that p partitions segment ab in the part to whole ratio of 1 to 3 wi
Amanda [17]

Answer:

P(7, -7)

Step-by-step explanation:

Xp = 6+ ⅓(9-6)= 6+ ⅓(3)=6+1 =7

Yp = -10 + ⅓(-1+10)= -10+⅓(9)= -10+3=-7

=> P (7, -7)

5 0
3 years ago
Suppose (1,19) is on the graph of y = f (x). Which of the following points lies on the graph of the transformed function y = f(1
o-na [289]

Answer:

(5,19) lies on the graph of the transformed function y = f(1/5x)

Step-by-step explanation:

Suppose (1,19) is on the graph of y = f (x)

the graph of the transformed function y = f(1/5x)

y=f(\frac{1}{5}x)

1/5 is multiplied with x  in f(x)

1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5

To make horizontal stretch we change the point

f(x)=f(bx) then (x,y) --->( x/b,y)

We divide the x coordinate by the fraction 1/5

(1,19) ----> (\frac{1}{\frac{1}{5}} , 19)= (5,19)

So (5,19) lies on the graph of the transformed function y = f(1/5x)

8 0
3 years ago
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