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lozanna [386]
4 years ago
9

X=Y + 2 X^2 + Y^2 +XY = 49 Find X, Y

Mathematics
2 answers:
Butoxors [25]4 years ago
7 0
Sub y+2 for x into second equaton

(y+2)^2+y^2+(y+2)y=49
y^2+4y+4+y^2+y^2+2y=49
3y^2+6y+4=49
minus 49 both sides
3y^2+6y-45=0
factor
3(y^2+2y-15)=0
3(y-3)(y+5)=0
set to zero
y-3=0
y=3
y+5=0
y=-5

y=3 and -5

sub back

x=y+2
x=3+2
x=5

x=y+2
x=-5+2
x=-3

the points are
(-3,-5) and (5,3)
puteri [66]4 years ago
5 0
X = (7 +  Y) (7 - Y) 

2 + Y
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Answer:

1) 36

b) 5

c) 3.0

Step-by-step explanation:

1) The recursive formula that defines the given sequence is

a_1=12 \\  a_n=a_{n-1}+4.

That means we keep adding 4 to the subsequent terms:

The sequence will be:

12,16,20,24,28,32,36,...

Therefore the seventh term is 36.

2) The sequence is recursively defined by;

a_1=20\\  a_n=a_{n-1} - 5

This means, we have to keep subtracting 5 from the subsequent terms.

The sequence will be;

20,15,10,5,...

Therefore the fourth term is 5

3) The sequence is recursively defined by:

f(n+1)=f(n)+0.5

where f(1)=-1.5

This means that, the subsequent terms can be found by adding 0.5 to the previous terms.

The sequence will be:

-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....

Therefore f(10)=3.0

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Answer:

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Step-by-step explanation:

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