The ship is 88.8 miles far from the port at 4 pm.
Given,
The displacement from 1 to 3 in the afternoon.
D1 = 30 miles/hr × 2 hr
= 60 miles to the north
The displacement from 3 till 4 in the afternoon.The ship changes its course 20 degrees eastward at 3 o'clock.
Therefore, D2 = 30 miles/hr × 1 hr
= 30 miles to the 20° north eastward
By combining two vectors, the resulting displacement:
D = √((D1 ₊ D2 × cos(20°))² ₊ (D2 × sin(20°))²
D = √((60 ₊ 30 × cos (20°))² ₊ (30 × sin(20°))²
D = 88.8 miles
Hence the ship is 88.8 miles far away from the port at 4 pm.
Learn more about "Law of sines and cosines" here-
brainly.com/question/13098194
#SPJ10
Seven less than the quotient of a number and 12 is 4 and 3.
Answer:
The height of the spanning tree is one by the breadth-first search at the central vertex of Wn.
Step-by-step explanation:
The graph is connected and has a spanning tree where the tree can build using a depth-first search of the graph. Start with chosen vertex, the graph as the root, and root add vertices and edges such as each new edge is incident with vertex and vertices are not in path. If all vertices are included, it will do otherwise, move back to the next level vertex and start passing. It is for depth-first search. For breadth-first search, start with chosen vertex add all edges incident to a vertex. The new vertex is added and becomes the vertices at level 1 in the spanning tree, and each vertex at level 1 adds each edge incident to vertex and other vertex connected to the edge of the tree as long as it does not produce.
All the factors of 32 include: 1,2,4,8,16,32
Hope this helps! (:
It seems okay to me (if that what your asking) I don't know this subject very well ut the part your working on " I'm familiar with ?" Don't be surprised if I was wrong buuuuut it does look okay to me "(the answer)".
