All categories

2 years ago

1. Write a short definition of each statistical term (mean, median, and mode).

Mathematics

1 answer:

pshichka [43]2 years ago

8 0

Answer:

Mean- Average
Median- the middle number in a sorted, ascending or descending
Mode- the most commonly observed value in a set of data

Using the example of- 1, 2, 2, 3, 3, 3, 4, 5, 6, 7

Mean- Average, (the sum of every value)/10(# of values)= 3.2

Median- 3 (even though there are 2 3s, but add them up and divide the sum by 2)

Mode- 3

3. Well... you could use these data to do science reports etc, ofc in the world of academics, you would need to use this kind of statistics terms a lot. In normal life, you might have to compare the price of similar products and see which is the best to purchase, seeing the value of the median of the entire set of data.

Step-by-step explanation:

You might be interested in

Maths<br>-|-30-(10-20)|-|5-(10-15)|=?<br>If someone helped me , I would be grateful

defon

Answer:

-30

Step-by-step explanation:

-|-30-(10-20)|-|5-(10-15)|=-|-30-(-10)|-|5-(-5)|

=-|-30+10|-|5+5|

=-|-20|-|10|

=-(20)-(10)

= -20-10

= -30

4 0

4 years ago

Explain the level of uncertainties involve in concept of probability. The next generation of miniaturized wireless capsules with

RUDIKE [14]

Answer:

a) the probability that Both motors will operate satisfactorily in the capsule 0.6222

b) the probability that One motor will operate satisfactorily and the other will not is 0.3556

Step-by-step explanation:

Given that;

total number of motors N = 10

number of motors will not operate satisfactory m = 2

number of motors randomly selected n = 2

let X be number of motors will that will not operate successfully

here, X≅Hyper geometric (x; N,n,m)

The probability mass function of x is;

P (X = x)= { m } {N - m }

{x } {n - x}

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ N }

{ n }

the probability that both motors will operate satisfactorily in the capsule i.e no motor will not operate satisfactory

P(X= 0) = { 2 } { 10 - 2 }

{0 } { 2 - 0}

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

P (X = 0) = { 2 } { 8}

{ 0 } { 2 }

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

p(P= 0)=1×28 / 45 = 28/45 = 0.6222

Therefore the probability that Both motors will operate satisfactorily in the capsule 0.6222

the probability that one motor will operate satisfactorily and the other will not.

P(X=1) = { 2 } { 10 - 2 }

{ 1 } { 2 - 1 }

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

P(X=1) = { 2 } { 8 }

{ 1 } { 1 }

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

P(X=1) = 2×8 / 45 = 16/45 = 0.3556

Therefore the probability that One motor will operate satisfactorily and the other will not is 0.3556

3 0

3 years ago

3(x - 2) + 48 = -3x

kow [346]

Answer: X=-7

Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

3x - 6

Step 2: Consider the equation as a whole with the newly part of the equation from step 1, as it is a part of the equation

Therefore, re-written as,

3x - 6 + 48 = -3x

Step 3: Evaluate the re-written equation

Using basic mathematics skills, we can evaluate the following,

3x - 6 + 48 = -3x ➡ -6 + 48 = -6x ➡ 42 = -6x ➡ -7 = x

As shown, the answer is x=-7.

8 0

3 years ago

1.7 degrees Fahrenheit drops every thousand feet. The temperature on the ground is 63.7 Fahrenheit. What will the temperature be

Oksanka [162]

Answer:

The answer to your question is Final temperature = 60.3°F

Step-by-step explanation:

I include the process in the attachment

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20

ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

$\sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}$

$\sf a^{-m}=\dfrac{1}{a^m}$

First convert radical form to exponent form and then apply exponent law.

$\sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}$

$\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}$

$= \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}$

3 0

2 years ago