Answer:
x= -3
Step-by-step explanation:
9x+3= -24
9x = -27
x=-3
Answer:
See attachment
Step-by-step explanation:
A function is given to us and we need to tell which graph represents the given function. The function given to us is,
Let's find out at which points do the graph Intersects x axis / finding the roots. For that substitute f(x) = 0 , we have ,
Equate each factor by 0 ,
Therefore the graph will intersect x axis at x is equal to -1 and x is equal to -3 .
On looking at the given graphs in the options the second graph intersects x axis at -1 and -3 .
<u>Hence</u><u> </u><u>the </u><u>second</u><u> </u><u>option</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u><u> </u>
{ See attachment }
Just to remove ambiguities, the bar over the expression means it's repeating itself to infinity.

notice, the idea being, you multiply it by 10 at some power, so that you move the "recurring decimal" to the other side of the point, and then split it with a digit and "x".
now, you can plug that in your calculator, to check what you get.
Answer:
6(2) + 6(1) = 18
Step-by-step explanation:
<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.