The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.
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How do we calculate the amount invested?</h3>
Let x represents the amount invested in the first account.
Therefore, we have:
Amount invested in the second account = x - 500
Interest income from first account = 3% * x = 0.03x
Interest income from second account = 5% * (x - 500) = 0.05x - 25
Total interest income = 0.03x + 0.05x - 25 = 719
Solving for x, we have:
0.08x = 719 + 25
x = 744 / 0.08
x = $9,300
Substituting for x, we have:
Amount invested in the second account = $9,300 - $500 = $8,800
Learn more about the amount invested here: brainly.com/question/24132106.
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Answer:
The answer would be:
B. ∠DEC is an exterior angle.
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hihhihihih
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-2
Step-by-step explanation:
M = (y - yo/x - xo)
(-6 + 2) / (0 + 2)
-4 / -2
= - 2
