I’m sorry, I wish I knew this one and I would help
Answer:
- AP
- tₙ = (n-2)k² + (2n - 3)k + n
Step-by-step explanation:
<u>Given sequence:</u>
- -k² - k + 1, k + 2, k² + 3k + 3, 2k² + 5k + 4, ...
We can see apart from the second term all terms are 2nd degree trinomial so it is not a GP.
Let's find the difference: to determine if it is a AP:
- k + 2 - (-k² - k + 1) = k + 2 + k² + k -1 = k² + 2k + 1
- k² + 3k + 3 - (k + 2) = k² + 3k + 3 - k - 2 = k² + 2k + 1
- 2k² + 5k + 4 - (k² + 3k + 3) = 2k² + 5k + 4 - k² - 3k - 3 = k² + 2k + 1
As we see the difference is common and it confirms the sequence is AP.
<u>First term is </u>
<u>Common difference is </u>
<u>nth term is:</u>
- tₙ = a₁ + (n-1)d
- tₙ = -k² - k + 1 + (n-1)(k² + 2k + 1) =
- -k² - k + 1 + (n-1)k² + (n-1)*2k + n-1 =
- (n-2)k² + (2n - 3)k + n
9514 1404 393
Answer:
$794.30
Step-by-step explanation:
The account balance for principal P invested at rate r compounded daily for t years is ...
A = P(1 +r/365)^(365t)
We have P=$9538, r=0.08, t=1, and we want the value of P-A, the interest earned.
P-A = P(1 +0.08/365)^365 -1) = $9538(1.08327757 -1) ≈ $794.30
The interest earned in one year is $794.30.
Answer:
24 apples
Step-by-step explanation:
set up the problem 6=0.25X. then divide 6 by 0.25 to get X by itself. 24 is the answer.
