Option 1: PV = $400,000
Option 2: Receive (FV) $432,000 in one year
PV = FV(1/(1+i)^n), where i= 8% = 0.08, n = 1 year
PV = 432,000(1/(1+0.08)^1) = $400,000
Option 3: Receive (A) $40,000 each year fro 20 years
PV= A{[1-(1+i)^-n]/i} where, n = 20 years
PV = 40,000{[1-(1+0.08)^-20]/0.08} = $392,725.90
Option 4: Receive (A) $36,000 each year from 30 years
PV = 36,000{[1-(1+0.08)^-30]/0.08} = $405,280.20
On the basis of present value computations above, option 4 is the best option for Kerry Blales. This option has the highest present value of $405,280.20
Answer:
The National Credit Union Association is a entity that monitors and regulate the Credit Unions which are organizations that are part of a cooperative and give credit to its members.
It was created in 1934 by the president Franklin Delano Roosevelt.
Answer:
True
Explanation:
According to the IRS:
- ordinary expenses are expenses that are common and accepted in a company's trade or industry.
- necessary expenses are expenses that help your company carry on its normal business.
Tax deductible expenses must be ordinary, necessary, and reasonable.
Answer:
The correct answer is 31 customers per day.
Explanation:
Consider the current capacity requirement as = x
Management wants to have a capacity cushion = 8%.
So the utilization is required = 100% - 8% = 92%
A process of currently services an average of 43 customers per day and utilization is 90%.
Expected Demand=70%= 70 ÷ 100 = 0.70
Current utilization = 90% = 0.90
Let Capacity requirement = X
Capacity requirement ÷ required utilization = Expected Demand rate × current service rate ÷ current utilization rate
X ÷ 0.92 = 0.70 × 43 ÷ 0.90
X = 0.70 × 43 ÷ 0.90 × 0.92
= 30.76 or 31
Needed capacity requirement is 31 customer per day.
The correct answer for the for loop is:
for (int i=1; i<200; i++){
if ((i%2)==0 && (i%3)==0){
cout << i << " ";
}
}
Python offers three options for running the loops. For iterating repeatedly through a sequence, use a for loop (that is either a list, a tuple, a dictionary, a set, or a string). This functions more like an iterator method seen in other object-oriented programming languages and is less like the for keyword found in other programming languages. The for loop allows us to run a series of instructions once for each element of a list, tuple, set, etc. There is no need to set an indexing variable before using the for loop.
Write a for loop that prints, in ascending order, all the positive integers less than 200 that are divisible by both 2 and 3, separated by spaces.
Learn more about loops here:
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