Based on the power, move the decimal point that many spaces to the right. (e.g., If it's 7.9 × 10^3, then move the decimal three spaces to the right, and you'd get 7900.)

3.14159 × 10^7 = 31415900

9.897752 × 10^6 = 9897752

2.468 × 10^7 = 24680000

Out of all the numbers mentioned in the question, 71,224,900 is the only one that's greater than 3.14159 × 10^7 = 31415900.

3 0

3 years ago

Find the dimensions of the rectangle with area 256 square inches that has minimum perimeter, and then find the minimum perimeter

mezya [45]

Answer:

Dimensions: $A=a\cdot b=256$

Perimiter: $P=2a+2b$

Minimum perimeter: [16,16]

Step-by-step explanation:

This is a problem of optimization with constraints.

We can define the rectangle with two sides of size "a" and two sides of size "b".

The area of the rectangle can be defined then as:

$A=a\cdot b=256$

This is the constraint.

To simplify and as we have only one constraint and two variables, we can express a in function of b as:

$b=\frac{256}{a}$

The function we want to optimize is the diameter.

We can express the diameter as:

$P=2a+2b=2a+2*\frac{256}{a}$

To optimize we can derive the function and equal to zero.

$dP/da=2+2\cdot (-1)\cdot\frac{256}{a^2}=0\\\\\frac{512}{a^2}=2\\\\a=\sqrt{512/2}= \sqrt {256} =16\\\\b=256/a=256/16=16$

The minimum perimiter happens when both sides are of size 16 (a square).

4 0

2 years ago

If f(1) = 7 and f(n) = 5(n-1) + 2, then f(4) =

Igoryamba

Answer:

Step-by-step explanation:

f(n)=5(n-1)+2

f(4)=5(4-1)+2

=5×3+2

=17

hope it helps

plz. mark as brainliest

4 0

2 years ago

Given a parabola with the vertex at the origin and the directrix at x=7 determine the direction the parabola opens. A. down B. l

Valentin [98]

I think the answer is b but im not sure

5 0

2 years ago

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