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3 years ago

The circumference of a circle is 5 π cm. What is the area of the circle?

Mathematics

1 answer:

LekaFEV [45]3 years ago

7 0

The answer is 6.25 pi cm squared

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The Venn diagram shows the results of two events resulting from rolling a number cube.

tankabanditka [31]

Answer:

$P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{1}{3}$

$P(A) =\frac{2}{3}$

$P(B) =\frac{1}{2}$ .

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

$P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}$

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

$P(A) = \frac{4}{6} = \frac{2}{3}$

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

$P(B) = \frac{3}{6} = \frac{1}{2}$ .

Now

$P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}$

6 0

3 years ago

The area of a rectangle is 440 square inches. The length of the rectangle is 29 inches more than its width. What is the length o

Andreyy89

The length of regtangle is 40 inches

3 0

3 years ago

Solve for the variable z to 4 = 8/5

Shkiper50 [21]

Answer:

Alright well solve for z by simplifying by both sides of the equation, then isolating the variable

Exact form: z = 2/5

Decimal form: o.4 Hope this helps :)

Step-by-step explanation:

5 0

3 years ago

Y= x + 2<br> y= x + 6<br> How many solutions

Alona [7]

$there \: is \: not \: any \: solutin \: for \: it \\ x + 2 = x + 6 \\ 2 = 6 \: is \: wrong$

7 0

2 years ago

Which quadratic function in vertex form can be represented by the graph that has a vertex at (3, -7) and passes through the poin

yarga [219]

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=3\\ k=-7 \end{cases}\implies y=a(x-3)^2-7\qquad \textit{we also know that} \begin{cases} x=1\\ y=-10 \end{cases} \\\\\\ -10=a(1-3)^2-7\implies -3=a(-2)^2\implies -3=4a\implies -\cfrac{3}{4}=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-\cfrac{3}{4}(x-3)^2-7~\hfill$

5 0

2 years ago