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natita [175]
3 years ago
8

Please help me I really need someone's helppp

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0
Alright, the ray <u>bisects</u> the angle, meaning each side has a value half of the measure of the original angle.
Since PQR is 82º, both halves equal 41º.
So, since (10x+1) is one of those two halves, we know 10x+1=41.
Now, we just solve.
10x+1=41
-1         -1
10x=40
/10
x=4º
soldier1979 [14.2K]3 years ago
5 0
Its an acute angle, im in 6th grade, and your in high school so..... im sorry if i get it wrong, but hey! i tried! lol
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The original figure that is being reflected is called a(n) _____.
miskamm [114]

Answer:

image

Step-by-step explanation:

im like 99% sure according to my knowledge i aint a nerd but it should be the answer dawg

5 0
4 years ago
Simplify each expression to a single trig function or number cosx(secx-cosx)
AlladinOne [14]
I did this test  b4, yours is answer #number 12

Convert things to their basic forms. 
<span>Remember a few identities </span>
<span>sin^2 + cos^2 = 1 so </span>
<span>sin^2 = 1 - cos^2 and </span>
<span>cos^2 = 1 - sin^2 </span>

<span>I'm going to skip typing the theta symbol, just to make things faster. Just assume it is there and fill it in as you work the problems. </span>

<span>Follow along to see how each problem was worked out. You'll catch on to the general technique. </span>

<span>====== </span>
<span>1. sec θ sin θ </span>
<span>1/cos * sin = sin/cos = tan </span>

<span>2. cos θ tan θ </span>
<span>cos * sin/cos = sin </span>

<span>3. tan^2 θ- sec^2 θ </span>
<span>sin^2 / cos^2 - 1/cos^2 </span>
<span>(sin^2 - 1)/cos^2 </span>
<span>-(1-sin^2)/cos^2 </span>
<span>-cos^2/cos^2 </span>
<span>-1 </span>

<span>4. 1- cos^2θ </span>
<span>sin^2 </span>

<span>5. (1-cosθ)(1+cosθ) </span>
<span>Remember (a+b)(a--b) = a^2 - b^2 </span>
<span>1-cos^2 = sin^2 </span>

<span>6. (secx-1) (secx+1) </span>
<span>sec^2 -1 </span>
<span>1/cos^2 - 1 </span>
<span>1/cos^2 - cos^2/cos^2 </span>
<span>(1-cos^2)/cos^2 </span>
<span>sin^2/cos62 </span>
<span>tan^2 </span>

<span>7. (1/sin^2A)-(1/tan^2A) </span>
<span>1/sin^2 - 1/(sin^2/cos^2) </span>
<span>1/sin^2 - cos^2/sin^2 </span>
<span>(1-cos^2)/sin^2 </span>
<span>sin^2/sin^2 </span>
<span>1 </span>

<span>8. 1- (sin^2θ/tan^2θ) </span>
<span>1-sin^2/(sin^2/cos^2) </span>
<span>1 - sin^2*cos^2/sin^2 </span>
<span>1-cos^2 </span>
<span>sin^2 </span>


<span>9. (1/cos^2θ)-(1/cot^2θ) </span>
<span>1/cos^2 - 1/(cos^2/sin^2) </span>
<span>1/cos^2 - sin^2/cos^2 </span>
<span>(1-sin^2)/cos^2 </span>
<span>cos^2/cos^2 </span>
<span>1 </span>

<span>10. cosθ (secθ-cosθ) </span>
<span>cos *(1/cos - cos) </span>
<span>1-cos^2 </span>
<span>sin^2 </span>

<span>11. cos^2A (sec^2A-1) </span>
<span>cos^2 * (1/cos^2 - 1) </span>
<span>1 - cos^2 </span>
<span>sin^2 </span>


<span>12. (1-cosx)(1+secx)(cosx) </span>
<span>(1-cos)(1+1/cos)cos </span>
<span>(1-cos)(cos + 1) </span>
<span>-(cos-1)(cos+1) </span>
<span>-(cos^2 - 1) </span>
<span>-(-sin^2) </span>
<span>sin^2 </span>

<span>13. (sinxcosx)/(1-cos^2x) </span>
<span>sin*cos/sin^2 </span>
<span>cos/sin </span>
<span>cot </span>

<span>14. (tan^2θ/secθ+1) +1 </span>
<span>(sin^2/cos^2)/(1/cos) + 2 </span>
<span>sin^2/cos + 2 </span>
<span>sin*tan + 2 </span>
5 0
3 years ago
Select each pair of functions that are inverses of each other:
Ganezh [65]

Option first, and option second represent the function;  f(x) and g(x) are inverses of each other option first, and option second are correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a shown function in the picture.

As we know if the function f(x) has double ordered (x, y) that satisfies the function.

Then it's inverse of a function g(x) must have ordered pair (y, x)

f(x) = {(-5,-9), (-3, -4), (0, 1), (3, 7), (6, 13)}

g(x) = {(-9,-5), (-4,-3), (1, 0), (7,3), (13,6)}

As we can see in the f(x) and g(x) they both have ordered pair (x, y) in f(x) and (y, x) in the g(x).

The f(x) and g(x) are inverses of each other.

f(x) = x + 7

g(x) = x - 7

To find the inverse of f(x)

Interchange the value of f(x) and x

x → g(x)

f(x) → x

x = g(x) + 7

g(x) = x -7

The f(x) and g(x) are inverses of each other.

The table does not represent any relation that shows that the f(x) and g(x) are inverses of each other.

Thus, option first, and option second represent the function;  f(x) and g(x) are inverses of each other option first, and option second are correct.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

4 0
2 years ago
Pls help me 20 points
horsena [70]

Answer: 36

Step-by-step explanation:

-3 to the power of -2 is 9

2 to the power of 1 is 4

when you multiply that u get 36

3 0
3 years ago
A baker has 5 pounds of sugar she divides them equally into three containers she then uses one container to bake a pie write an
balu736 [363]
I think 5 divide by 3
7 0
4 years ago
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