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Eduardwww [97]
3 years ago
12

The table shows the pricing for four different types of apples. Which type cost the least per kilogram? How do you get the answe

r?
1. $4 for 1.5 kg
2. $5 for 2.0 kg
3. $7 for 2.5 kg
4. $8 for 2.5 kg
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

Least cost per kilogram is "$5 for 2.0 kg"

Step-by-step explanation:

To get cost per kilogram, we divide the cost given by the kg given.

1. We need to divide 4 by 1.5 to get cost per kilogram.

Cost/Kg = \frac{4}{1.5}=2.67

2. We need to divide 5 by 2.0 to get cost per kilogram.

Cost/Kg = \frac{5}{2.0}=2.5

3. We need to divide 7 by 2.5 to get cost per kilogram.

Cost/Kg = \frac{7}{2.5}=2.8

4. We need to divide 8 by 2.5 to get cost per kilogram.

Cost/Kg = \frac{8}{2.5}=3.2

As we can see, the second option costs the least per kilogram.

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<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

f(x)=ax^2+bx+c

Here we know that the leading coefficient a=1 so we reduce our equation to:

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The roots are those values at which g(x)=0

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x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\  49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\

Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\  49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0

So we have:

(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}

Finding c from (1):

33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

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