-6 + 10 = 4, and then you use inverse operations, which would be / = x and + = -, so you would get 4 * 6, which would equal 24.
4x^2 + x + 3 = 0
x = [-1 +/- sqrt (1^2 - 4 * 4 * 3)] / 8 = - 1 +/- sqrt ( --47) / 8
= ( - 1 +/- sqrt47i) / 8 = -0.125 + 0.857i , -0.125 - 0.857i
You can have a lot of ways to solve this problem, but I'm going for solving for the lawn's area directly instead of solving the reserved section and subtracting it from the total area of the whole place.
First, cut the lawn so that it becomes two shapes: a rectangle, and a triangle. Solve for both areas.
A(r) = lw
A(r) = (14)(16)
A(r) = 224 square feet
A(t) = bh/2
A(t) = (8)(14) / 2
A(t) = 112 / 2
A(t) = 56 square feet
Add the two areas:
A(r) + A(t) = Area of lawn
224 square feet + 56 square feet = 280 square feet.
The area of the lawn, therefores, is 280 ft^2.
Answer:
Step-by-step explanation:
We know that the equation that models the height of the ball as a function of time is 
.
Where the initial speed is 80 feet.
When the ball lands on the ground, its height will be 
.
So to know how long it will take the ball to reach the ground, equal h (t) to zero and solve for t.
To solve this quadratic equation we use the quadratic formula.
For an equation of the form:
The quadratic formula is:
In this case
Then
We take the positive solution
Considering the relationship between velocity, distance and time, it is found that the total distance traveled was of 380 miles.
<h3>What is the relationship between velocity, distance and time?</h3>
Velocity is <u>distance divided by time</u>, that is:
v = d/t.
For the first day, we have that:
v = 40, t = t + 2, d = d + 20, hence:
40 = (d + 20)/(t + 2)
For the second day, we have that:
v = 60
60 = d/t
d = 60t
Then, replacing in the first equation:
40 = (60t + 20)(t + 2)
60t + 20 = 40t + 80
20t = 60
t = 3.
Then the distances are given by:
- First day: d = 60t + 20 = 60 x 3 + 20 = 200 miles.
- Second day: d = 60t = 60 x 3 = 180 miles.
- Total: 200 miles + 180 miles = 380 miles.
More can be learned about the relationship between velocity, distance and time at brainly.com/question/28143163
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