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worty [1.4K]
3 years ago
5

Jskawlowlekdkckfkdkdkdkkfkfkfkfkfkr

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0
Use photo math it works very well!
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Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
Evaluate the integral using the indicated trigonometric substitution.<br> -
Studentka2010 [4]
By simplifing it i think
3 0
3 years ago
If a polygon is a regular pentagon, then it has 5 sides.
mina [271]
If a polygon has 5 sides, then it is a regular pentagon
False: regular pentagon = equiangular.  There are pentagons that have 5 sides that are not equiangular
3 0
3 years ago
Read 2 more answers
A data set includes the following SAT scores: 340, 560, 480, 680, 700. Suppose an additional score of 700 is inserted in the dat
DIA [1.3K]

Answer:

Step-by-step explanation:

Let's first arrange it in ascending order :

340, 480, <u>560</u>, 680, 700

<u>560</u> is clearly the median.

Now add an additional score of 700 to the data :

340, 480, <u>560, 680</u>, 700 ,700

<u>560, 680</u> is separating both halves but is not the median

Median = (560+680)/2

             = 1240 / 2

Median  = 620

7 0
3 years ago
What is the sum of all the integers between the square root of 19 and the square root of 77?
Artist 52 [7]
Since we are only dealing with integers, we do not need to worry about decimals. Therefore, finding the exact values of sqrt(19) and sqrt(77) is not important. We can just estimate.

19 is between 16 and 25 (which are 4^2 and 5^2), so the square root of 18 is some number between 4 and 5.

77 is between 64 and 81 (which are 8^2 and 9^2), so the square root of 77 is some number between 8 and 9.

So the integers (whole numbers) that are between our two sqaure roots are 5, 6, 7, and 8.

Add them up and we have our answer.

5+6+7+8 = 26




4 0
3 years ago
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