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dexar [7]
3 years ago
7

So my cousin sent me this saying that she needs help . I use to know how to do this but I forgot . Can anyone help me with this

Mathematics
1 answer:
Fofino [41]3 years ago
8 0
Im pretty sure it is either c or d

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Can<br> You<br> Help me<br> It’s hard
anyanavicka [17]

Answer:

16.8 + (-18.6)

Step-by-step explanation:

A subtraction symbol and adding a negative are the same

8 0
3 years ago
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What are the coefficients in the expression 5x3 + 14x2 - 2x + 6?
Lostsunrise [7]

Answer: 5,14 and -2

Step-by-step explanation:

The coefficient  is the number next to the variable.

So this case the coefficients are 5,14 and -2

6 0
3 years ago
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Find the difference. write the difference in lower term 8 ⅓-5
sergejj [24]

Given data:

The given expression is 8 ⅓-5.

The given expression can be written as,

\begin{gathered} 8\frac{1}{3}-5=\frac{25}{3}-5 \\ =\frac{25-15}{3} \\ =\frac{10}{3} \end{gathered}

Thus, the difference of the given expression is 10/3.

5 0
1 year ago
-6 is less than w, and w is less than 8
Mashutka [201]

Answer:

-6<w<8

Step-by-step explanation:

-6<w<8

6 0
3 years ago
Can anyone help me about question 2
madreJ [45]

9514 1404 393

Answer:

  3(4/3)^2543

Step-by-step explanation:

Using logarithms base 2, we have ...

  (a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

  \log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}

and the 2544th term is ...

  \boxed{\log_2{a_{2544}}=3\left(\dfrac{4}{3}\right)^{2543}}

8 0
3 years ago
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