Equation of the perpendicular
y= 2x+6
slope of the perpendicular = 2
slope of the req. line = -1/2
equation of the req. line
y - y1 = m(x - x1)
y - 2 = -1/2(x + 4)
2(y - 2) = -1(x + 4)
2y - 4 = -x - 4
2y = -x
y = (-1/2)x
this is your req. equation of line.
32-3/5, 49-1/2, 64-2/3, 81-1/4, 125-2/3
Answer:
84
Step-by-step explanation:
Since we are given line OP perpendicular to line DR, then angles PDR and ODR are right angles.
Angles PDA and ADR are complementary.
Angles ODU and UDR are complementary.
Angles ADR and UDR are given as congruent.
We can conclude that angles PDA and ODU are congruent.
By AA Similarity, triangles APD and UMD are similar.
DP/DM = PA/MU
3.75/10 = 4.5/MU
3.75MU = 10 × 4.5
MU = 12 (altitude of triangle DUO)
OD = OM + MD = 4 + 10 = 14 (base of triangle DUO)
area = base × height / 2
area = 14 × 12 / 2
area = 84
Answer:
5x2 - 10
Step-by-step explanation:
F(5x - 3)
(5x - 3)2 + 1
5x2 - 9 + 1
5x2 - 10
I think that the answer is A
