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bulgar [2K]
4 years ago
11

(9m+6)+(-5m-6) a. 4m+12 b.14m+12 c.14m-12 d.4m

Mathematics
2 answers:
Arisa [49]4 years ago
8 0

Answer:

A. 4m+12

Step-by-step explanation:

artcher [175]4 years ago
5 0
C.) 14-12

move the like terms first.

(9m+5m)+(-6-6)
=14m-12
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Chris ran 25 miles, while Bill ran 5 miles. How many times farther did Chris run than Bill?
mixer [17]

Answer: Chris ran 20 miles more then Bill

Step-by-step explanation:

25(Chris) - 5(Bill) = 20 Miles

Hope this helped, have a great day/night!

~IFoundJiminsLostJams~

8 0
3 years ago
Read 2 more answers
Help me solve this... i have a time limit so answer fast!!!
coldgirl [10]

Answer:

Hypotenuse² = Base² + Altitude²

35² = 15² + x²

1225 = 225 + x²

x² = 1225 - 225

x² = 1000

<u>X = 10√10</u>

6 0
3 years ago
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Distributive property of 8 x 31
solong [7]
Your answer would be 248
7 0
3 years ago
HELP ME PLEASE!!
LUCKY_DIMON [66]

Using a system of equation, we have that:

a)

  • x, which is the cost of on-site service.
  • y, which is the cost of at-store service.
  • z, which is the cost of by-mail service.

b)

The system is:

x = 3y

z = y - 10

15x + 40y + 5z = 3100

c)

The cost of one on-site repair service is of $90.

Item a:

The variables are:

  • x, which is the cost of on-site service.
  • y, which is the cost of at-store service.
  • z, which is the cost of by-mail service.

Item b:

On-site service costs <u>3 times as much as at-store service</u>, thus:

x = 3y

By mail service costs <u>$10 less than at-store</u>  service, thus:

z = y - 10

Last week, the shop completed <u>15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100</u>, thus:

15x + 40y + 5z = 3100

The system is:

x = 3y

z = y - 10

15x + 40y + 5z = 3100

Item c:

  • The cost of one on-site repair service is x.
  • First, replacing the first two equations into the third, we find y, and then with it we find x.

15x + 40y + 5z = 3100

15(4y) + 40y + 5(y - 10) = 3100

60y + 40y + 5y = 3150

105y = 3150

y = \frac{3150}{105}

y = 30

Then

x = 3y = 3(30) = 90

The cost of one on-site repair service is of $90.

A similar problem is given at brainly.com/question/24823220

3 0
3 years ago
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
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