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Nezavi [6.7K]
4 years ago
14

State how many imaginary and real zeros the function has. f(x) = x3 + 5x2 + x + 5

Mathematics
1 answer:
Firlakuza [10]4 years ago
7 0

Step-by-step explanation:

f(x) = x³ + 5x² + x + 5

f(x) = x² (x + 5) + x + 5

f(x) = (x² + 1) (x + 5)

The function has one real root (x = -5) and two imaginary roots (x = ±i).

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