Answer:
oo freeeeeee I was just the same thing in common use today in the vwjabahqjvqio
we are given

now, we can compare it with

we can find b
we get

now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
Answer: Diego, 4a + 9b is equivalent
Step-by-step explanation:
7a + 5b - 3a + 4b
= (7a - 3a) + (5b + 4b) We rerange the variables, and put them together with (), which make it more clear to solve.
= 4a + 9b
Answer:
(4) -1.
Step-by-step explanation:
First evaluate f(π/2) which is 2 * π/2 = π.
So g(f(π/2)) = g(π)
= cos π
= -1.
Answer:
WHA
Step-by-step explanation: