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alukav5142 [94]
2 years ago
6

Write a function that receives two numbers, m and n and calculates and displays the sum of the integers from m to n. For example

, if the arguments are m = 3 and n = 7, the function should calculate 3 + 4 + 5 + 6 + 7
Computers and Technology
1 answer:
Evgesh-ka [11]2 years ago
7 0

Answer:

The program to this question as follows:

Program:

//header file

#include <stdio.h> //defining header file

void inc(int m,int n) //defining method inc

{

   int sum, i; //declaring variable

   sum=m; //holding value of m variable

   for(i=++m;i<=n;i++) //loop for calculate number between given range  

   {

   sum=sum+i; //adding value

   }

   printf("sum of the integer is : %d",sum);//print value

}

int main() //defining method

{

   int m,n; //defining integer variable

   printf("Enter m value: "); //message

   scanf("%d",&m); //input value by user in variable

   printf("Enter n value: "); //message

   scanf("%d",&n);//input value by user in variable

   inc(m,n); //calling method

   return 0;

}

Output:

Enter m value: 3

Enter n value: 7

sum of the integer is :25

Explanation:

In the above code, an "inc" function is declared, that accepts integer parameters that are "m and n", inside the method two integer variable "sum and i" is declared, which is used in the loop.

  • The loop uses the user parameter to count value and uses the sum variable to calculate there sum.
  • In the main method, two integer variable n and m are declared, which take value from the user end, and at the last, we call the inc method, that prints sum value.
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Answer:

check the explanation

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to solve the question, we will write this set of codes;

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7 0
3 years ago
The speed of sound depends on the material the sound is passing through. Below is the approximate speed of sound (in feet per se
german

Answer:

The Java Program for the given problem is as below. Directly copy the code and run it on your machine.

Explanation:

Refer the Screenshots attached for the output.

import java.io.BufferedReader;

import java.io.InputStreamReader;

public class TheSpeedOfSound {

public static void main(String[] s)

{

String medium;

double distance;

double time;

try{

BufferedReader choice = new BufferedReader(new InputStreamReader(System.in));

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medium = choice.readLine(); // reading input i.e. air, water or steel

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System.out.print("It will take " + time + " seconds.");

break;

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time = distance/4900;

System.out.print("It will take " + time + " seconds.");

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}

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catch(Exception e){

e.printStackTrace();

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3 years ago
Wi-Fi Protected Access (WPA) fixes critical vulnerabilities in the earlier wired equivalent privacy (WEP) standard. Understandin
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Since Wi-Fi Protected Access (WPA) fixes critical vulnerabilities in the earlier wired equivalent privacy (WEP) standard, the attacks that is related to encrypted wireless packets is option A: IV attacks.

<h3>Describe an IV attack.</h3>

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Note that A binary vector used to initialize the encryption process for a plaintext block sequence in order to boost security by adding more cryptographic variance and to synchronize cryptographic hardware. The initialization vector is not required to be kept secret.

Learn more about Wi-Fi Protected Access  from

brainly.com/question/13068630
#SPJ1

See full question below

Wi-Fi Protected Access (WPA) fixes critical vulnerabilities in the earlier wired equivalent privacy (WEP) standard. Understanding that WPA uses a combination of an RC4 stream cipher and Temporal Key Integrity Protocol (TKIP), this makes a wireless access point NOT vulnerable to which of the following attacks when related to encrypted wireless packets?

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Malware

Ransoware

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murzikaleks [220]

Answer:

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Having explained the options one after the other, <em>the file manager </em>is the answer to this question.

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