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labwork [276]
3 years ago
15

Which type of file can be opened directly into Excel?

Computers and Technology
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

Explanation: Select Change.

Select More apps.

Select the desired app, then select the to Always use this app checkbox.

Select the OK button.

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Which of the following is NOT an example of written communication?
Veronika [31]

Answer:A conversation between co-workers

Explanation:

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3 years ago
With modeling and simulation, we model the system and then test the ______________ to gather test predictions.
Kobotan [32]

Answer:

With modeling and simulation, we model the system and then test the system to gather test predictions.

Explanation:

You would have to test the system in order to see if it's working right and everything is all good with the system.

I hope this helped. I am sorry if you get this wrong.

4 0
3 years ago
A. Convert decimal 37 to binary
lisabon 2012 [21]

Answer:

100101

25

5E7

101000011100

Explanation:

4 0
3 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
I need someone to help me like rnnnnn please
nevsk [136]

.send me 1000 ruppes i will answer each and every question you send send 1000 ruppes to this number 93257 50999

6 0
3 years ago
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