The length and width of the toolbox given the diagonal is 45 inches and 15 inches respectively.
<h3>Triangle</h3>
- Width of the triangle = w
- Length of the triangle = 3w
- Diagonal = 30 inches
Hypotenuse ² = opposite ² + adjacent ²
30² = w² + (3w²)
30² = 4w²
900 = 4w²
w² = 900/4
= 225
w = √225
w = 15
Therefore,
Width of the triangle = w
= 15 inches
Length of the triangle = 3w
= 3(15)
= 45 inches
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4.3 x 10 to the power of 2
H^3+3h^2x+3hx^2+x^3 should be the answer
is there more to this question
