Answer:
Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Step-by-step explanation:
We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.
<em>Let X = incomes for the industry</em>
So, X ~ N(
)
Now, the z score probability distribution is given by;
Z =
~ N(0,1)
where,
= mean income of firms in the industry = 95 million dollars
= standard deviation = 5 million dollars
So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)
P(X < 100) = P(
<
) = P(Z < 1) = 0.8413 {using z table]
Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Answer:
-24
Step-by-step explanation:
-4-8= -12
8-2=6
12+6=18
-12b+6c+18
Greatest common factor = 6
-12/6=-2
6/6=1
18/6=3
D 6(-2b+1c+3)
-12(2)+6(-3)+18
-24+(-18)+18
-42+18= -24
-24
Answer:
16. (80)(60) = 4800
17. (500)(600) = 300000
18. (700)(800) = 560000 a). high
Step-by-step explanation:
Answer:
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Answer:
270
Step-by-step explanation:
Since you have the value of x as 90
3x=3*90
3x=270