<h3><u>Answer:</u></h3>
<h3>
<u>Solution:</u></h3>
We are given that the arithmetic progression is defined by :
➝ 2n + 1
<em>Therefore, </em>
- <u>For </u><u>first </u><u>term</u>
➙ n = 1
➝ 2 × 1 + 1
➝ 2 + 1
➝ 3
- <u>For </u><u>second </u><u>term</u>
➙ n = 2
➝ 2 × 2 + 1
➝ 4 + 1
➝ 5
- <u>Common </u><u>difference</u>
➙ 2nd term - 1st term
➝ 5 - 3
➝ 2
<h3><u>More </u><u>information</u><u>:</u></h3>
- The difference between the successive term and the preceding term is the difference of an arithmetic progression. It is always same for the same arithmetic progression.
Answer: 4.27% of adults in the USA have stage 2 high blood pressure.
Step-by-step explanation:
Let x be a random variable that denotes a person with high blood pressure .
Given: Average blood pressure: 
Standard deviation: 
Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher.
The probability that an adult in the USA have stage 2 high blood pressure:
![P(x\geq160)=P(\dfrac{x-\mu}{\sigma}}\geq\dfrac{160-122}{22})\\\\=P(z\geq1.72)\ \ \ [z=\dfrac{x-\mu}{\sigma}]\\\\=1-P(z](https://tex.z-dn.net/?f=P%28x%5Cgeq160%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%7D%5Cgeq%5Cdfrac%7B160-122%7D%7B22%7D%29%5C%5C%5C%5C%3DP%28z%5Cgeq1.72%29%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28z%3C1.72%29%5C%5C%5C%5C%3D1-0.9573%5C%20%5C%20%5BBy%5C%20p-value%5C%20table%5D%5C%5C%5C%5C%3D0.0427%3D4.27%5C%25)
Hence, 4.27% of adults in the USA have stage 2 high blood pressure.
Answer:
if ABCD is a rhombus then the diagonal of rhombus bisect it into two equal triangles.
Step-by-step explanation:
In triangles ABC and CDA,
- AB= CD (S) because rhombus has equal sides.
- BC = AD (S) as as reason 1.
- AC= AC (S) being common side of both triangles
so the triangles are congruent to each other by S.S.S. fact/ axiom
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