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3 years ago

700/200 in a terminating decimal

Mathematics

1 answer:

Aneli [31]3 years ago

8 0

700/200=7/2 because devide by 100 and then=3 1/2 and half is .5 so= 3.5

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Locating Zeros of Polynomial Function:<br>Approximate the real zeros to the nearest tenth

solmaris [256]

we are given

$f(x)=2x^4-x^3+x-2$

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

$f(-2)=2(-2)^4-(-2)^3+(-2)-2$

$f(-2)=36$

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

so, this is FALSE

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Answer:

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Step-by-step explanation:

.....................

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