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2 years ago

9

Rob is cooking a cake.The recipe calls for 9 cups of flour.He has already put in 3 cups. How many more cups does he need to put

in?

1 answer:

svetoff [14.1K]2 years ago

7 0

Answer:

9-3= 6 Cups

Step-by-step explanation:

Recipe needs 9 cups of flour, Rob has added 3 cups already so he needs to add 6 more cups to make it 9 cups.

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The area of a square is 36 square feet. each side of the square measures

choli [55]

6 ft for each side, bc area is side times side, which 6x6=36

6 0

2 years ago

Read 2 more answers

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

The number 66 is increased to 72. What is the percentage by which the number was increased, to the nearest tenth of a percent?

Lunna [17]

Answer:

The increase is 9.1%

Step-by-step explanation:

<u>Step 1: Make an equation </u>

$66 * x = 72$

$66x = 72$

<u>Step 2: Divide both sides by 66 </u>

$66x / 66 = 72 / 66$

$x = 1.09090$

<u>Step 3: Find the increased </u>

$1 - 1.09090$

$0.091 * 100$

9.1%

Answer: The increase is 9.1%

6 0

2 years ago

Pls help me and thank ya!!

algol13

Answer:

Option 1

Step-by-step explanation:

Rational numbers do not have infinite decimals.

Option 1:

-5, 3/4 and √49 are all rational. Correct

√49 = 7

3/4 = 0.75

-5 = -5

Option 2:

1/4 = 0.25

5 = 5

√12 = 3.4641...

Incorrect

Option 3:

-1/2 = -0.5

-3 = -3

√8 = 2.82841...

Incorrect

Option 4:

1/7 = 0.142857...

9 = 9

√11 = 3.31662...

Incorrect

5 0

2 years ago

A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to

Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

= $2\pi r$

$=(2\times 3.14 \times 32) ft$

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0

3 years ago