i know im a little late, but the answer is -0.5198
P.S i love your profile lol XD
think of it like this, after 1 hour there is 2 inches of rain, after 2 hours there is 4 inches of rain, and after 10, there should be 20, so, as it runs 1 it should rise 2.
Answer:
Speed of Jet in Still Air = 265 miles per hour
Speed of Wind = 22 miles per hour
Step-by-step explanation:
Let x be speed of jet
and c be speed of wind
We know D = RT, where
D is distance
R is rate
T is time
For first leg:
1435 miles in 5 hours, the rate is:
Rate = 287 mph
For second leg:
1215 miles in 5 hours, the rate is:
Rate = 243 mph
So 287 is with wind and 243 against wind, thus we can write:
x + c = 287
x - c = 243
Adding gives us:
2x = 530
x = 265 miles per hour [still rate]
Speed of wind:
x + c = 287
265 + c = 287
c = 22 miles per hour [speed of wind]
Answer:
x(x-7)+4(x-1)/(x-1)(x+1)(x-7)
Step-by-step explanation:
Given the expression x/x²-1 + 4/x²-6x-7
Factorize x²-6x-7
x²-6x-7
= x²-7x+x-7
= x(x-7)+1(x-7)
= (x+1)(x-7)
Replace back into the expression given
x/x²-1 + 4/x²-6x-7
= x/x²-1 + 4/ (x+1)(x-7)
= x/(x+1)(x-1) + 4/(x+1)(x-7)
Find the LCM
= x(x-7)+4(x-1)/(x-1)(x+1)(x-7)
This gives the required expression
B is the answer due to when finding the solution you have to equalize the problems and solve.
