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saul85 [17]
4 years ago
13

30 POINTS PLEASE HELP!!

Mathematics
1 answer:
Sedbober [7]4 years ago
3 0

A polynomial p is graphed. What could be the equation of p?

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A pair of pant and a t-shirt cost $34. If the pant cost $6.28 more than the shirt, how much did the pant cost?
Delvig [45]

Answer

23.28

Step-by-step explanation:

34 ÷ 2 = 17 and 17 + 6.28 = 23.28

7 0
4 years ago
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Elijah is planning a circular flower garden with a 12-foot diameter. He will put plastic edging along the flowerbed. How many fe
brilliants [131]

Answer:

37.7 ft

Step-by-step explanation:

c=πd (circumference= 3.14*diameter)

c=3.14*12

c=37.68 ft

rounded to tenths place-37.7 ft

3 0
3 years ago
The length of the rectangle below is (2x-3) and the width is (x+7). Find the area of the rectangle in terms of x.
krek1111 [17]

Answer:

rgfb

Step-by-step explanation:

2 because if you divide

5 0
3 years ago
A number problem states, “–5 times a number, minus 22 gives a result of 23.” What is the number?
Serggg [28]

Answer:

im pretty sure its -9

Step-by-step explanation:

the equation explained would look something like this...

-5x-22=23

so you would isolate the variable by first adding 22 to both sides and the dividing by -5 on both sides

-5x-22=23

    +22  +22

-5x/-5=45/-5

x=-9

8 0
4 years ago
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Prove cosh 3x = 4 cosh^3 x - 3 cosh x.
Snezhnost [94]
Prove we are to prove  4(coshx)^3 - 3(coshx) we are asked to prove 4(coshx)^3 - 3(coshx) to be equal to cosh 3x
= 4(e^x+e^(-x))^3/8 - 3(e^x+e^(-x))/2 = e^3x /2 +3e^x /2 + 3e^(-x) /2 + e^(-3x) /2 - 3(e^x+e^(-x))/2 = e^(3x) /2 + e^(-3x) /2 = cosh(3x) = LHS Since y = cosh x satisfies the equation if we replace the "2" with cosh3x, we require cosh 3x = 2 for the solution to work. 
i.e. e^(3x)/2 + e^(-3x)/2 = 2 
Setting e^(3x) = u, we have u^2 + 1 - 4u = 0 
u = (4 + sqrt(12)) / 2 = 2 + sqrt(3), so x = ln((2+sqrt(3))/2) /3, Or u = (4 - sqrt(12)) / 2 = 2 - sqrt(3), so x = ln((2-sqrt(3))/2) /3, 
Therefore, y = cosh x = e^(ln((2+sqrt(3))/2) /3) /2 + e^(-ln((2+sqrt(3))/2) /3) /2 = (2+sqrt(3))^(1/3) / 2 + (-2-sqrt(3))^(1/3) to be equ
= 4(e^x+e^(-x))^3/8 - 3(e^x+e^(-x))/2 
= e^3x /2 +3e^x /2 + 3e^(-x) /2 + e^(-3x) /2 - 3(e^x+e^(-x))/2 
= e^(3x) /2 + e^(-3x) /2 
= cosh(3x) 
= LHS 

<span>Therefore, because y = cosh x satisfies the equation IF we replace the "2" with cosh3x, we require cosh 3x = 2 for the solution to work. </span>

i.e. e^(3x)/2 + e^(-3x)/2 = 2 

Setting e^(3x) = u, we have u^2 + 1 - 4u = 0 

u = (4 + sqrt(12)) / 2 = 2 + sqrt(3), so x = ln((2+sqrt(3))/2) /3, 
Or u = (4 - sqrt(12)) / 2 = 2 - sqrt(3), so x = ln((2-sqrt(3))/2) /3, 

Therefore, y = cosh x = e^(ln((2+sqrt(3))/2) /3) /2 + e^(-ln((2+sqrt(3))/2) /3) /2 
= (2+sqrt(3))^(1/3) / 2 + (-2-sqrt(3))^(1/3)
3 0
4 years ago
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