Answer:
1.5
18 and 33
Step-by-step explanation:2.
c
Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3
<u>Solution:</u>
We have been given two equations which are as follows:
3x - 4y = -24 ----- eqn 1
x + 4y = 8 -------- eqn 2
We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.
We rearrange eqn 2 as follows:
x + 4y = 8
x = 8 - 4y ------eqn 3
Now we substitute eqn 3 in eqn 1 as follows:
3(8 - 4y) -4y = -24
24 - 12y - 4y = -24
-16y = -48
y = 3
Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:
x = 8 - 4(3)
x = 8 - 12 = -4
Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.
Answer:
the answer is 22.36 or 22.4
Step-by-step explanation:
Answer:A for the first one and C for the second one
Step-by-step explanation:
Answer:
-4
Step-by-step explanation:
[√2(cos(3π/4) + i sin(3π/4))]⁴
(√2)⁴ (cos(3π/4) + i sin(3π/4))⁴
4 (cos(3π/4) + i sin(3π/4))⁴
Using De Moivre's Theorem:
4 (cos(4 × 3π/4) + i sin(4 × 3π/4))
4 (cos(3π) + i sin(3π))
3π on the unit circle is the same as π:
4 (cos(π) + i sin(π))
4 (-1 + i (0))
-4
