The time, in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters
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Answer:
The ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.
Step-by-step explanation:
Let the Area of smaller watch face be
Also Let the Area of Larger watch face be
Also Let the radius of smaller watch face be
Also Let the radius of Larger watch face be
Now given:
We need to find the ratio of the radius of the smaller watch face to the radius of the larger watch face.
Solution:
Since the watch face is in circular form.
Then we can say that;
Area of the circle is equal 'π' times square of the radius 'r'.
framing in equation form we get;
So we get;
Substituting the value we get;
Now 'π' from numerator and denominator gets cancelled.
Now Taking square roots on both side we get;
Hence the ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.