Question

The time, in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given by this
equation
t = va
Which equation expresses din terms of tanda?
OA d = 2at?
OB.
OC. d =
= VA
OD. d = 1

Answer 1

Answer:

$d=\dfrac{t^2}{a}$

Step-by-step explanation:

The time  in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given by this  equation.

t = va

We need to find the expression for d in terms of t and a.

As velocity = distance/time

$t=\dfrac{d}{t}a\\\\t^2=da\\\\d=\dfrac{t^2}{a}$

So, the distance d is $\dfrac{t^2}{a}$.