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3 years ago

Simplify 4^9 X 4^3 please (:

Mathematics

2 answers:

Radda [10]3 years ago

8 0

Answer:

4^12

Step-by-step explanation:

4^9 * 4^3

We know that a^b * a^c = a^ (b+c)

4^9 * 4^3

4^(9+3)

4^12

alexdok [17]3 years ago

5 0

Answer:

4 ^ 12

Step-by-step explanation:

4 ^ 9 x 4 ^ 3

You add the exponents when the bases are the same.

9 + 3 = 12

4 ^ 12

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4 years ago

Twelve more than the quotient of six divided by three

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3 years ago

A $300 bike is marked down to $175 what is the percent markdown to the nearest whole percent?

LUCKY_DIMON [66]

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4 years ago

Read 2 more answers

A small plane travels north at 240 mph. A jet leaves the same airport 30 minutes later and follows the other plane at 360 mph. H

kifflom [539]

Solution here,

let the both planes covers same distance x while over taking.

For the small plane, let time be t.

speed= 240 mph

now,

distance covered by it,

x=240t--------(1)

For jet plane,let the time be t'.

speed=36mph

since it is flewed after 30 mins, it can be written as,

t'=t-30 min=t-0.5 hr

now distance covered by it,

c=360t'=360(t-0.5)=360t-180----------(2)

equating (1) and (2)

240t=360t-180

or, -120t=-180

or, t=1.5 hr

therefore two planes wiil meet after 1.5 hrs.

putting the value of t in (1)

x=240×1.5=360 m

therefore they travel through 360 m from the airport whlie over taking.

For the first car,

speed=50 Kmph

let it covers x distance at time t

so,diatance x=50t--------(1)

For the second car,

speed=45 Kmph

according to the question, in time t, it will covers the distance (x-20)Km

so, distance(x-20)=45t

or, x=45t+20---------(2)

equating (1) and (2),

50t=45t+20

or, 5t=20

or, t=4 hrs.

therefore cars will be apart of 20 km after 4 hrs.

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3 years ago

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prohojiy [21]

Answer:

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Step-by-step explanation:

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3 years ago

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