Can you guys help me please
2 answers:
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<u>Answer:</u>
1 , (Answer)
<u>Step-by-step explanation:</u>
Since, 8 chips are selected at random and 5 are there defectives in the lot, So, at least (8 - 5) = 3 chosen chips will be non - defective.
So, P ( At least two of selected part is non defective ) = 1 .
P(first and second samples are defective)
=
P ( first, second and third samples are defective)
=
So,
=
=
= (Answer)